- 2078 Baisakh · 3 marks
Principal stresses; Mohr circle at failure
Short answer
Major principal stress σ1 is the largest normal stress on a plane with zero shear; minor σ3 is the smallest. If σ1 increases at constant σ3, the Mohr circle expands until it touches the failure line, causing failure. For a cohesionless soil, the failure envelope passes through the origin and sin φ = (σ1-σ3)/(σ1+σ3).
Define major and minor principal stresses. What happens if the value of major principal stress increases while minor principal stress remains constant? Draw the Mohr circle of stresses at failure with Mohr-Coulomb failure line for soil having only angle of internal friction.
Major and minor principal stresses
At any point in a stressed soil there are three mutually perpendicular planes on which the shear stress is zero. These are the principal planes, and the normal stresses on them are the principal stresses.
- Major principal stress : the largest of the three normal stresses.
- Minor principal stress : the smallest of the three normal stresses.
- The third is the intermediate principal stress .
Effect of increasing with constant
The deviator stress increases, so the Mohr circle grows larger (its centre moves right and its radius increases). The maximum shear stress, , also increases. When the circle becomes tangent to the Mohr-Coulomb envelope, the soil fails. cannot be increased beyond this point, because a Mohr circle cannot cut the failure envelope: the soil has already failed.
Mohr circle at failure for a soil with only (cohesionless)
The failure line passes through the origin, and the circle is tangent to it:
tau / tau = sigma tan(phi)
| T/
| /.-''-.
| /' '.
| / phi C \
+--+------+-----+---- sigma
0 s3 s1
From the right-angled triangle :
and the failure plane is at to the major principal plane.
✓ Answer checked by Claude Opus 5.5 (high effort)
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