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State Mohr-Coulomb failure criterion

Short answer

The Mohr-Coulomb failure criterion states that soil fails when shear stress on a plane reaches τ_f = c + σ tan φ (effective stress: τ_f = c' + σ' tan φ'). The Mohr circle must not cross this line; failure occurs when it touches, on a plane inclined at 45°+φ/2 to major principal plane.

State Mohr-Coulomb's failure criterion.

Mohr-Coulomb failure criterion: a soil fails when the shear stress on any plane reaches the shear strength, which is a linear function of the normal stress on that plane:

τf=c+σtan⁡ϕ\tau_f = c + \sigma\tan\phi

In terms of effective stress, τf=c′+σ′tan⁡ϕ′\tau_f = c' + \sigma'\tan\phi'. Here cc is the cohesion intercept and ϕ\phi is the angle of shearing resistance (internal friction).

  • If the Mohr circle for a stress state lies wholly below the failure line, the soil is stable.
  • If the circle touches the line, the soil is on the point of failure.
  • A circle cannot extend above the line.

Failure occurs on a plane inclined at 45∘+ϕ/245^\circ+\phi/2 to the major principal plane.

✓ Answer checked by Claude Opus 5.5 (high effort)

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