- 2068 Chaitra · 8 marks
Local attraction, BC 79°30′ and DE 82°15′
Short answer
No line is free; all stations suspected. Included-angle method: interior angles sum 541°00′, error +1°00′, correction −0°12′ per angle. The most reliable line DE (smallest diff) is adopted as 262°30′. Corrected fore bearings: AB 188°36′, BC 74°54′, CD 30°27′, DE 262°30′, EA 230°18′.
Following are the bearings observed in a compass traverse survey. At what stations do you suspect local attraction? Correct them by applying a suitable correction method.
| Line | FB | BB |
|---|---|---|
| AB | 191°30′ | 13°00′ |
| BC | 79°30′ | 256°30′ |
| CD | 32°15′ | 210°30′ |
| DE | 262°45′ | 82°15′ |
| EA | 230°15′ | 53°00′ |
No line is free (the differences are 178°30′, 183°00′, 181°45′, 180°30′ and 177°15′), so all stations are suspected of local attraction. Line DE has the smallest difference (0°30′), so D and E are the least affected; the included-angle method is used.
Local attraction at a station is detected by comparing the fore bearing (FB) and back bearing (BB) of each line: if there is no local attraction at either end, exactly.
Step 1: Check each line
| Line | FB | BB | FB − BB | Remark |
|---|---|---|---|---|
| AB | 191°30′ | 13°00′ | 178°30′ | Differs by −1°30′ |
| BC | 79°30′ | 256°30′ | 183°00′ | Differs by +3°00′ |
| CD | 32°15′ | 210°30′ | 181°45′ | Differs by +1°45′ |
| DE | 262°45′ | 82°15′ | 180°30′ | Differs by +0°30′ |
| EA | 230°15′ | 53°00′ | 177°15′ | Differs by −2°45′ |
Step 2: Included (interior) angles
The included angle at a station uses the FB of the line leaving it and the BB of the line arriving at it, both observed at the same station, so local attraction cancels in the angle.
The sum of the interior angles should be .
| Station | Angle between | Observed | Corrected |
|---|---|---|---|
| A | AE and AB | 138°30′ | 138°18′ |
| B | BA and BC | 66°30′ | 66°18′ |
| C | CB and CD | 135°45′ | 135°33′ |
| D | DC and DE | 52°15′ | 52°03′ |
| E | ED and EA | 148°00′ | 147°48′ |
Sum observed = 541°00′; error = +1°00′; correction per angle = −0°12′ (equal distribution, since each angle is measured with the same care).
No line has FB − BB = 180°. Line DE has the smallest difference (+0°30′), so it is the most reliable; its adopted bearing is the mean of the FB and (BB ± 180°) = 262°30′.
Step 3: Corrected bearings from the corrected angles
Rule used: FB of next line = BB of previous line + interior angle (traverse run anticlockwise). Starting from DE = 262°30′ (BB 82°30′): EA = 82°30′ + 147°48′ = 230°18′, and so on round the traverse.
| Line | Observed FB | Correction | Corrected FB | Observed BB | Corrected BB |
|---|---|---|---|---|---|
| AB | 191°30′ | −2°54′ | 188°36′ | 13°00′ | 8°36′ |
| BC | 79°30′ | −4°36′ | 74°54′ | 256°30′ | 254°54′ |
| CD | 32°15′ | −1°48′ | 30°27′ | 210°30′ | 210°27′ |
| DE | 262°45′ | −0°15′ | 262°30′ | 82°15′ | 82°30′ |
| EA | 230°15′ | +0°03′ | 230°18′ | 53°00′ | 50°18′ |
Check: corrected FB − corrected BB = 180° for every line.
Interior angles from the corrected bearings
| Station | Interior angle |
|---|---|
| A | 138°18′ |
| B | 66°18′ |
| C | 135°33′ |
| D | 52°03′ |
| E | 147°48′ |
Sum = 540°00′ (as required).
Answer: Corrected bearings (FB): AB = 188°36′, BC = 74°54′, CD = 30°27′, DE = 262°30′, EA = 230°18′.
✓ Answer checked by Claude Opus 5.5 (high effort)
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