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Local attraction and true bearings, 7°W

Short answer

Local attraction at C, D, E: corrections to observed bearings are +2°30′, +1°15′, +0°15′. Corrected magnetic FB: AB 59°00′, BC 139°30′, CD 217°45′, DE 209°15′, EA 318°45′. True FB (declination 7°W): AB 52°00′, BC 132°30′, CD 210°45′, DE 202°15′, EA 311°45′.

The following bearings were observed with a compass for traversing. Find the amount of local attraction and correct the bearings as well as the true bearings if the magnetic declination is 7°W.

LineFBBB
AB59°00′239°00′
BC139°30′317°00′
CD215°15′36°30′
DE208°00′29°00′
EA318°30′138°45′

Line AB has FB − BB = 180°, so A and B are free. Stations C, D and E are suspected. Declination is 7° West, so true bearing = magnetic bearing − 7°.

Local attraction at a station is detected by comparing the fore bearing (FB) and back bearing (BB) of each line: if there is no local attraction at either end, FB−BB=180∘\text{FB} - \text{BB} = 180^\circ exactly.

Step 1: Check each line

LineFBBBFB − BBRemark
AB59°00′239°00′180°00′Free, difference = 180°
BC139°30′317°00′182°30′Differs by +2°30′
CD215°15′36°30′178°45′Differs by −1°15′
DE208°00′29°00′179°00′Differs by −1°00′
EA318°30′138°45′179°45′Differs by −0°15′

Line AB has a difference of exactly 180°, so stations A and B are free from local attraction. The other stations are corrected one after another, starting from B.

Step 2: Correct the stations in turn

  • Line BC: FB at B = 139°30′ is correct. The correct BB is 319°30′, observed 317°00′, so the correction at C is +2°30′.
  • Line CD: FB at C = 215°15′ with correction +2°30′ gives 217°45′. The correct BB is 37°45′, observed 36°30′, so the correction at D is +1°15′.
  • Line DE: FB at D = 208°00′ with correction +1°15′ gives 209°15′. The correct BB is 29°15′, observed 29°00′, so the correction at E is +0°15′.
  • Line EA (check): FB at E = 318°30′ with correction +0°15′ gives 318°45′. The correct BB is 138°45′, which equals the observed value, so A needs no correction, as expected.
StationABCDE
Correction00+2°30′+1°15′+0°15′

Stations affected by local attraction: C, D and E. The amount of local attraction at each is equal and opposite to the correction: C −2°30′, D −1°15′, E −0°15′ (the observed bearings there are too small).

Step 3: Corrected bearings

LineObserved FBCorrectionCorrected FBObserved BBCorrected BBTrue FBTrue BB
AB59°00′059°00′239°00′239°00′52°00′232°00′
BC139°30′0139°30′317°00′319°30′132°30′312°30′
CD215°15′+2°30′217°45′36°30′37°45′210°45′30°45′
DE208°00′+1°15′209°15′29°00′29°15′202°15′22°15′
EA318°30′+0°15′318°45′138°45′138°45′311°45′131°45′

Check: corrected FB − corrected BB = 180° for every line.

Answer: Corrected bearings (FB): AB = 59°00′, BC = 139°30′, CD = 217°45′, DE = 209°15′, EA = 318°45′. True bearings (FB): AB = 52°00′, BC = 132°30′, CD = 210°45′, DE = 202°15′, EA = 311°45′.

✓ Answer checked by Claude Opus 5.5 (high effort)

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