- 2066 Jestha · 8 marks
Local attraction and true bearings, 7°W
Short answer
Local attraction at C, D, E: corrections to observed bearings are +2°30′, +1°15′, +0°15′. Corrected magnetic FB: AB 59°00′, BC 139°30′, CD 217°45′, DE 209°15′, EA 318°45′. True FB (declination 7°W): AB 52°00′, BC 132°30′, CD 210°45′, DE 202°15′, EA 311°45′.
The following bearings were observed with a compass for traversing. Find the amount of local attraction and correct the bearings as well as the true bearings if the magnetic declination is 7°W.
| Line | FB | BB |
|---|---|---|
| AB | 59°00′ | 239°00′ |
| BC | 139°30′ | 317°00′ |
| CD | 215°15′ | 36°30′ |
| DE | 208°00′ | 29°00′ |
| EA | 318°30′ | 138°45′ |
Line AB has FB − BB = 180°, so A and B are free. Stations C, D and E are suspected. Declination is 7° West, so true bearing = magnetic bearing − 7°.
Local attraction at a station is detected by comparing the fore bearing (FB) and back bearing (BB) of each line: if there is no local attraction at either end, exactly.
Step 1: Check each line
| Line | FB | BB | FB − BB | Remark |
|---|---|---|---|---|
| AB | 59°00′ | 239°00′ | 180°00′ | Free, difference = 180° |
| BC | 139°30′ | 317°00′ | 182°30′ | Differs by +2°30′ |
| CD | 215°15′ | 36°30′ | 178°45′ | Differs by −1°15′ |
| DE | 208°00′ | 29°00′ | 179°00′ | Differs by −1°00′ |
| EA | 318°30′ | 138°45′ | 179°45′ | Differs by −0°15′ |
Line AB has a difference of exactly 180°, so stations A and B are free from local attraction. The other stations are corrected one after another, starting from B.
Step 2: Correct the stations in turn
- Line BC: FB at B = 139°30′ is correct. The correct BB is 319°30′, observed 317°00′, so the correction at C is +2°30′.
- Line CD: FB at C = 215°15′ with correction +2°30′ gives 217°45′. The correct BB is 37°45′, observed 36°30′, so the correction at D is +1°15′.
- Line DE: FB at D = 208°00′ with correction +1°15′ gives 209°15′. The correct BB is 29°15′, observed 29°00′, so the correction at E is +0°15′.
- Line EA (check): FB at E = 318°30′ with correction +0°15′ gives 318°45′. The correct BB is 138°45′, which equals the observed value, so A needs no correction, as expected.
| Station | A | B | C | D | E |
|---|---|---|---|---|---|
| Correction | 0 | 0 | +2°30′ | +1°15′ | +0°15′ |
Stations affected by local attraction: C, D and E. The amount of local attraction at each is equal and opposite to the correction: C −2°30′, D −1°15′, E −0°15′ (the observed bearings there are too small).
Step 3: Corrected bearings
| Line | Observed FB | Correction | Corrected FB | Observed BB | Corrected BB | True FB | True BB |
|---|---|---|---|---|---|---|---|
| AB | 59°00′ | 0 | 59°00′ | 239°00′ | 239°00′ | 52°00′ | 232°00′ |
| BC | 139°30′ | 0 | 139°30′ | 317°00′ | 319°30′ | 132°30′ | 312°30′ |
| CD | 215°15′ | +2°30′ | 217°45′ | 36°30′ | 37°45′ | 210°45′ | 30°45′ |
| DE | 208°00′ | +1°15′ | 209°15′ | 29°00′ | 29°15′ | 202°15′ | 22°15′ |
| EA | 318°30′ | +0°15′ | 318°45′ | 138°45′ | 138°45′ | 311°45′ | 131°45′ |
Check: corrected FB − corrected BB = 180° for every line.
Answer: Corrected bearings (FB): AB = 59°00′, BC = 139°30′, CD = 217°45′, DE = 209°15′, EA = 318°45′. True bearings (FB): AB = 52°00′, BC = 132°30′, CD = 210°45′, DE = 202°15′, EA = 311°45′.
✓ Answer checked by Claude Opus 5.5 (high effort)
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