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Local attraction in closed traverse ABCDEFA

Short answer

All lines have FB−BB differing from 180°, indicating local attraction at every station. Included angle sum is 720°30′, so +0°30′ error is corrected by –5′ per angle; adopting DE as most reliable (321°15′), corrected FB bearings: AB 216°00′, BC 135°40′, CD 80°40′, DE 321°15′, EF 246°10′, FA 298°35′.

The bearings of a closed traverse ABCDEFA are given as follows. Find the stations affected by local attraction and correct them if necessary.

LineFore BearingBack Bearing
AB216°30′36°10′
BC135°55′316°25′
CD81°30′260°30′
DE321°10′141°20′
EF246°20′66°50′
FA299°20′119°00′

Every line differs from 180° (by 0°20′, 0°30′, 1°00′, 0°10′, 0°30′ and 0°20′), so no station can be called free with certainty, and all stations are suspected of local attraction. Line DE has the smallest difference, so D and E are the least affected stations; the bearings are corrected using the included angles.

Local attraction at a station is detected by comparing the fore bearing (FB) and back bearing (BB) of each line: if there is no local attraction at either end, FB−BB=180∘\text{FB} - \text{BB} = 180^\circ exactly.

Step 1: Check each line

LineFBBBFB − BBRemark
AB216°30′36°10′180°20′Differs by +0°20′
BC135°55′316°25′179°30′Differs by −0°30′
CD81°30′260°30′181°00′Differs by +1°00′
DE321°10′141°20′179°50′Differs by −0°10′
EF246°20′66°50′179°30′Differs by −0°30′
FA299°20′119°00′180°20′Differs by +0°20′

Step 2: Included (interior) angles

The included angle at a station uses the FB of the line leaving it and the BB of the line arriving at it, both observed at the same station, so local attraction cancels in the angle.

The sum of the interior angles should be (2n−4)×90∘=720∘(2n-4)\times 90^\circ = 720^\circ.

StationAngle betweenObservedCorrected
AAF and AB97°30′97°25′
BBA and BC99°45′99°40′
CCB and CD125°05′125°00′
DDC and DE60°40′60°35′
EED and EF105°00′104°55′
FFE and FA232°30′232°25′

Sum observed = 720°30′; error = +0°30′; correction per angle = −0°05′ (equal distribution, since each angle is measured with the same care).

No line has FB − BB = 180°. Line DE has the smallest difference (−0°10′), so it is the most reliable; its adopted bearing is the mean of the FB and (BB ± 180°) = 321°15′.

Step 3: Corrected bearings from the corrected angles

Rule used: FB of next line = BB of previous line + interior angle (traverse run anticlockwise). Starting from DE = 321°15′ (BB 141°15′): EF = 141°15′ + 104°55′ = 246°10′, and so on round the traverse.

LineObserved FBCorrectionCorrected FBObserved BBCorrected BB
AB216°30′−0°30′216°00′36°10′36°00′
BC135°55′−0°15′135°40′316°25′315°40′
CD81°30′−0°50′80°40′260°30′260°40′
DE321°10′+0°05′321°15′141°20′141°15′
EF246°20′−0°10′246°10′66°50′66°10′
FA299°20′−0°45′298°35′119°00′118°35′

Check: corrected FB − corrected BB = 180° for every line, and working round the traverse returns to DE = 321°15′.

Answer: Corrected bearings (FB): AB = 216°00′, BC = 135°40′, CD = 80°40′, DE = 321°15′, EF = 246°10′, FA = 298°35′.

✓ Answer checked by Claude Opus 5.5 (high effort)

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