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Methods of reducing levels

Short answer

Height of instrument method: HI = RL + BS, RL = HI - staff reading; check ΣBS - ΣFS = last RL - first RL. Rise and fall method: rise/fall from consecutive readings; check ΣBS - ΣFS = ΣRise - ΣFall = last RL - first RL. HI is faster; rise and fall checks all readings.

What are the methods of reducing levels (height of instrument and rise and fall methods)? Explain briefly with arithmetic checks.

Reduction of levels is the calculation of the reduced level (RL) of each point from the staff readings entered in the level book. Two methods are used.

1. Height of instrument (HI) or height of collimation method

  • HI (the RL of the line of collimation) = RL of the BM + BS.
  • RL of any point = HI −- staff reading (IS or FS) on it.
  • At a change point, the new HI = RL of the CP + new BS.
HI=RL+BS,RL=HI−IS or FS\text{HI} = \text{RL} + \text{BS}, \qquad \text{RL} = \text{HI} - \text{IS or FS}

Arithmetic check: ΣBS−ΣFS=last RL−first RL\Sigma BS - \Sigma FS = \text{last RL} - \text{first RL}.

It is quicker and suitable when many intermediate sights are taken (profile and cross-section levelling), but the intermediate sights are not checked.

2. Rise and fall method

  • The difference between consecutive staff readings gives a rise or a fall.
  • If the second reading is less than the first, it is a rise: rise == previous reading −- present reading, and RL == previous RL ++ rise.
  • If it is greater, it is a fall, and RL == previous RL −- fall.

Arithmetic check:

ΣBS−ΣFS=ΣRise−ΣFall=last RL−first RL\Sigma BS - \Sigma FS = \Sigma \text{Rise} - \Sigma \text{Fall} = \text{last RL} - \text{first RL}

It checks every reading (including the intermediate sights), but takes more time. It is preferred for precise work, such as fly levelling and check levelling.

PointHI methodRise and fall method
SpeedFasterSlower
CheckOnly BS/FSAll sights
Suitable forMany intermediate sightsFew intermediate sights

Example (HI): BM RL 100.000, BS 1.500 gives HI 101.500; FS 0.800 on point P gives RL 100.700.

✓ Answer checked by Claude Opus 5.5 (high effort)

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