- 2074 Chaitra · 6 marks
Theodolite traverse ABCDA, booking format with VCR
Short answer
Mean directions computed; observed sum 360°02′55″, error +2′55″ distributed equally. Corrected angles: A=70°11′51.25″, B=89°08′01.25″, C=110°24′51.25″, D=90°15′16.25″. Missing VCR: FR (B-A)=239°45′40″, FL (D-C)=51°08′40″; vertical angles: −30°14′20″ and +38°51′20″.
The following observations were recorded in a theodolite traverse ABCDA. Compute the mean horizontal angles and the missing readings by entering the following readings in a standard booking format.
| Instrument Stations | Target Stations | HCR Direct | HCR Reversed | VCR FL | VCR FR |
|---|---|---|---|---|---|
| A | D | 89°59′50″ | 270°00′10″ | ||
| B | 160°12′40″ | 340°12′30″ | |||
| B | A | 90°00′00″ | 269°59′40″ | 120°14′20″ | ? |
| C | 179°08′40″ | 359°08′30″ | |||
| C | B | 90°00′00″ | 269°59′50″ | ||
| D | 200°25′40″ | 20°25′20″ | |||
| D | C | 90°00′10″ | 270°00′00″ | ? | 308°51′20″ |
| A | 180°16′10″ | 00°16′00″ |
Assumption: closed traverse ABCDA (four stations), angle sum 360°. The readings are entered in the standard booking format below.
Method. For each target the mean direction is found from the two faces:
The angle at a station = mean direction of the forward station - mean direction of the back station. For a closed traverse of sides, the sum of the interior angles must be ; the difference is the angular error, which is distributed equally among the angles (the angles are measured with the same instrument and care).
Field book and mean angles
| Inst. stn | Sighted to | Face L | Face R | Mean direction | Mean angle |
|---|---|---|---|---|---|
| A | D | 89°59′50″ | 270°00′10″ | 90°00′00″ | |
| B | 160°12′40″ | 340°12′30″ | 160°12′35″ | 70°12′35″ | |
| B | A | 90°00′00″ | 269°59′40″ | 89°59′50″ | |
| C | 179°08′40″ | 359°08′30″ | 179°08′35″ | 89°08′45″ | |
| C | B | 90°00′00″ | 269°59′50″ | 89°59′55″ | |
| D | 200°25′40″ | 20°25′20″ | 200°25′30″ | 110°25′35″ | |
| D | C | 90°00′10″ | 270°00′00″ | 90°00′05″ | |
| A | 180°16′10″ | 00°16′00″ | 180°16′05″ | 90°16′00″ |
Check and adjustment
Required sum = = 360°00′00″. Observed sum = 360°02′55″. Angular error = 360°02′55″ - 360°00′00″ = +0°02′55″. Correction per angle = -0°00′43.75″ (equal for all 4 angles).
| Angle at | Mean angle | Correction | Corrected angle |
|---|---|---|---|
| A | 70°12′35″ | -0°00′43.75″ | 70°11′51.25″ |
| B | 89°08′45″ | -0°00′43.75″ | 89°08′01.25″ |
| C | 110°25′35″ | -0°00′43.75″ | 110°24′51.25″ |
| D | 90°16′00″ | -0°00′43.75″ | 90°15′16.25″ |
| Sum | 360°02′55″ | -0°02′55″ | 360°00′00″ |
Answer: corrected horizontal angles: A = 70°11′51.25″, B = 89°08′01.25″, C = 110°24′51.25″, D = 90°15′16.25″.
Missing VCR readings
Missing VCR. For a vertical circle graduated as zenith angle, the sum of the face-left and face-right readings of the same target is 360° when the instrument has no index error. So the missing reading = 360° - the given reading. The vertical angle is (+ elevation, - depression).
| Observation | VCR Face left | VCR Face right | Vertical angle (90° - Z) |
|---|---|---|---|
| B to A | 120°14′20″ | 239°45′40″ | -30°14′20″ |
| D to C | 51°08′40″ | 308°51′20″ | +38°51′20″ |
✓ Answer checked by Claude Opus 5.5 (high effort)
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