- Asked 3/13
- 2074 Bhadra · 2 marks
- 2073 Bhadra · 1.5 marks
- 2070 Magh
z-transform of cos at
Short answer
Z[cos at] = z(z - cos aT) / (z^2 - 2z cos aT + 1) for |z| > 1. With T=1, it becomes z(z - cos a)/(z^2 - 2z cos a + 1).
Find the z-transform of cos at.
Take sampling period T, so x(kT) = cos(akT). Use Euler's formula:
cos at = (e^(iat) + e^(−iat))/2
and Z[e^(±iat)] = z/(z − e^(±iaT)) (ROC |z| > 1).
Z[cos at] = ½ [ z/(z − e^(iaT)) + z/(z − e^(−iaT)) ] = ½ · z [ (z − e^(−iaT)) + (z − e^(iaT)) ] / [ (z − e^(iaT))(z − e^(−iaT)) ]
Numerator: z[2z − 2cos aT]. Denominator: z² − z(e^(iaT) + e^(−iaT)) + 1 = z² − 2z cos aT + 1.
Answer:
Z[cos at] = z (z − cos aT) / (z² − 2z cos aT + 1), |z| > 1
(For T = 1: z(z − cos a)/(z² − 2z cos a + 1).)
✓ Answer checked by Claude Opus 5.5 (high effort)
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