- 2068 Bhadra · 8 marks
DC generator working and emf equation
Short answer
A DC generator converts mechanical energy to DC electrical energy by rotating conductors through a magnetic field (Faraday's law). The commutator mechanically rectifies the alternating emf. The average generated emf is E = PΦZN/(60A) volts, derived from flux cut per revolution ΦP, time per revolution 60/N, and series conductors per path Z/A.
Explain working principle of DC generator in detail and hence derive the expression of emf equation also.
A DC generator is a machine that turns mechanical power into DC electrical power. Its action is based on Faraday's laws of electromagnetic induction.
Working principle
- When a conductor is moved in a magnetic field so that it cuts the lines of flux, an emf is induced in it: e = B l v (V). The direction is given by Fleming's right-hand rule.
- The armature conductors, rotated by a prime mover, cut the flux of the N and S poles. The emf induced in a coil is alternating, because each conductor passes alternately under N and S poles.
- The commutator is a mechanical rectifier. As the coil emf reverses, the commutator segment connection to the brush also reverses, so the brush polarity does not change.
- The brushes deliver unidirectional current to the load. The magnitude depends on speed and flux.
- Field excitation is supplied either by a separate source (separately excited) or by the machine itself (self-excited: shunt, series, compound).
prime mover -> rotating armature -> commutator -> brushes -> load
(N rpm) (cuts flux Φ) (AC to DC)
Energy flow: mechanical input − (friction, windage, iron, copper losses) = electrical output.
Derivation of EMF equation
Let P = number of poles, Φ = flux per pole (Wb), Z = total armature conductors, A = parallel paths, N = speed (rpm).
- Flux cut by a conductor in one revolution: dΦ = ΦP
- Time for one revolution: dt = 60/N s
- Average emf generated per conductor: e = dΦ/dt = ΦPN/60 volts
- Number of conductors in series in each parallel path = Z/A
- Emf of the generator = emf per path
E_g = (ΦPN/60) × (Z/A) = PΦZN / (60A) volts
| Winding | A | E_g |
|---|---|---|
| Lap | P | ΦZN/60 |
| Wave | 2 | PΦZN/120 |
For a given machine, E_g = KΦN with K = PZ/(60A), which shows that emf depends on the flux per pole and the speed.
✓ Answer checked by Claude Opus 5.5 (high effort)
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