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Synchronous generator principle and EMF equation

Short answer

A synchronous generator converts mechanical energy to AC by rotating a DC-excited rotor field, inducing emf in stationary armature conductors via Faraday's law. Frequency f = PNs/120. RMS phase emf E = 4.44 f Φ T kp kd, where T is turns per phase, kp and kd are pitch and distribution factors.

Explain the working principle of synchronous generator and also derive the E.M.F equation.

A synchronous generator (alternator) converts mechanical energy into AC electrical energy by electromagnetic induction, at a frequency fixed by its speed.

Working principle

  1. The rotor carries the field winding, excited by DC through slip rings (or a brushless exciter); it produces alternate N and S poles.
  2. The prime mover (water/steam turbine, engine) drives the rotor at synchronous speed NsN_s.
  3. The rotating flux cuts the stationary three-phase armature conductors on the stator. By Faraday's law, an emf e=Blve = Blv is induced; its direction is given by Fleming's right-hand rule.
  4. Under a N pole the emf is in one direction, under a S pole in the other, so an alternating emf results. One cycle is produced per pair of poles: f=PNs120f = \dfrac{PN_s}{120}.
  5. The three phase windings are displaced by 120° electrical, giving three balanced emfs 120° apart.
  6. When load is connected, current flows and power is delivered; the field current is adjusted to keep voltage constant.
   N  ->  rotor turns  ->  S
   |  flux cuts stator     |
   v  conductors           v
  e = B l v  (sinusoidal, f = P Ns / 120)

EMF equation

Let PP = poles, Φ\Phi = flux per pole (Wb), NsN_s = rpm, ZZ = conductors per phase in series, T=Z/2T = Z/2 turns per phase.

Flux cut per revolution=PΦTime for one revolution=60Ns sAverage emf per conductor=PΦNs60With f=PNs120:=2fΦ VAverage emf per phase=2fΦ×Z=4fΦT VRMS emf per phase=1.11×4fΦT=4.44 fΦT V\begin{aligned} \text{Flux cut per revolution} &= P\Phi \\ \text{Time for one revolution} &= \frac{60}{N_s}\ \text{s} \\ \text{Average emf per conductor} &= \frac{P\Phi N_s}{60} \\ \text{With } f = \frac{PN_s}{120}:\quad &= 2f\Phi\ \text{V} \\ \text{Average emf per phase} &= 2f\Phi\times Z = 4f\Phi T\ \text{V} \\ \text{RMS emf per phase} &= 1.11\times4f\Phi T = 4.44\,f\Phi T\ \text{V} \end{aligned}

using form factor 1.11 for a sine wave. For practical windings, which are short-pitched and distributed:

Eph=4.44 kp kd f Φ TE_{ph} = 4.44\,k_p\,k_d\,f\,\Phi\,T

where

  • pitch factor kp=cos⁡(α/2)k_p = \cos(\alpha/2), α\alpha = angle by which the coil is short of 180° electrical;
  • distribution factor kd=sin⁡(mβ/2)msin⁡(β/2)k_d = \dfrac{\sin(m\beta/2)}{m\sin(\beta/2)}, mm = slots per pole per phase, β\beta = slot angle.

Line voltage: EL=3EphE_L = \sqrt3 E_{ph} for star, EL=EphE_L = E_{ph} for delta.

✓ Answer checked by Claude Sonnet 5.5

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