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Torque-slip curve and rotor resistance
Short answer
Maximum torque occurs at slip s_m = R2/X2 and is independent of rotor resistance. Increasing rotor resistance shifts the peak to higher slip, raising starting torque; when R2 = X2, starting torque equals maximum torque.
Explain the torque-slip characteristics of a 3-phase induction motor. Show the condition for which the maximum torque develops in the induction motor. Discuss the effect of variation of rotor resistance on this maximum torque.
Torque-slip characteristic
For a 3-phase induction motor, the torque at slip s is
T = (3 / ω_s) × s E₂² R₂ / (R₂² + (sX₂)²) N·m
where E₂, R₂ and X₂ are the standstill rotor emf, resistance and reactance per phase, and ω_s is the synchronous speed in rad/s.
T |
| Tmax
| *******
| * *****
| * ******
| * ***** Tst
| *
| *
|*
+---------+------------------+--> s
0 s_m 1
(N = Ns) (N = 0)
- At s = 0, T = 0. For small s, T ∝ s (stable working region, nearly linear).
- T rises to T_max at s = s_m, then falls as T ∝ 1/s (unstable region) down to the starting torque T_st at s = 1.
- Normal full-load slip is only 2 to 5 %, in the stable linear region.
Condition for maximum torque
Set dT/ds = 0:
(R₂² + s²X₂²) − 2s²X₂² = 0, so R₂² = s²X₂²
s_m = R₂ / X₂, and T_max = 3E₂² / (2ω_sX₂)
Maximum torque occurs when the rotor resistance per phase equals the rotor reactance at that slip.
Effect of rotor resistance
- T_max does not depend on R₂, but the slip at which it occurs (s_m = R₂/X₂) increases in proportion to R₂.
- Higher R₂ shifts the peak towards s = 1 (lower speed), and the starting torque increases.
- If R₂ = X₂, then s_m = 1, and the starting torque equals the maximum torque.
- If R₂ is increased beyond X₂, the starting torque begins to fall.
R2 small R2 larger R2 = X2
(low Tst) (higher Tst) (Tst = Tmax)
T | ** T | ******* T | ******
| * ** | ** *** | ***
|* ** | * | **
| ****** | * | **
| * |* |**
+---------------> s +---------------> s +---------------> s
0 1 0 1 0 1
| Rotor resistance | s_m | T_max | T_st |
|---|---|---|---|
| Low | small | same | low |
| Medium | moderate | same | higher |
| R₂ = X₂ | 1 | same | = T_max |
This is why a slip-ring induction motor, with external resistance added to the rotor circuit, gives a high starting torque with a low starting current. The extra resistance is cut out gradually as the motor speeds up, to keep good efficiency and low slip.
✓ Answer checked by Claude Opus 5.5 (high effort)
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