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Double field revolving theory

Short answer

A pulsating flux is resolved into two equal rotating fluxes of half amplitude, rotating oppositely at synchronous speed. At standstill, their torques cancel, so the motor is not self-starting; once rotating, forward torque exceeds backward torque.

What do you understand by double field revolving theory? Explain it with the help of a neat diagram.

Double field revolving theory (DFRT)

A single-phase winding carrying alternating current produces a pulsating (alternating) flux along a fixed axis: ϕ=ϕmcos⁡ωt\phi = \phi_m\cos\omega t. According to the double field revolving theory, this pulsating flux is equivalent to two rotating fluxes, each of constant magnitude ϕm/2\phi_m/2, rotating at synchronous speed Ns=120fPN_s = \frac{120f}{P} in opposite directions.

ϕmcos⁡ωt=ϕm2ejωt+ϕm2e−jωt\phi_m\cos\omega t = \frac{\phi_m}{2}e^{j\omega t} + \frac{\phi_m}{2}e^{-j\omega t}
  • ϕf\phi_f: the forward-rotating component (in the direction of the rotor).
  • ϕb\phi_b: the backward-rotating component (in the opposite direction).
 phi_f = phi_m/2 -->  (anticlockwise)
          \   /
   phi_b   \ /  resultant = phi_m cos(wt)
 = phi_m/2  X   along fixed axis (pulsating)
 (clockwise)

At every instant the components perpendicular to the winding axis cancel, and the components along the axis add, giving the pulsating flux ϕmcos⁡ωt\phi_m\cos\omega t.

Rotor behaviour

Each field induces rotor currents and produces its own torque. For a rotor speed NrN_r in the forward direction:

  • Slip with respect to the forward field: sf=s=Ns−NrNss_f = s = \frac{N_s - N_r}{N_s}
  • Slip with respect to the backward field: sb=2−ss_b = 2 - s

The net torque is T=Tf−TbT = T_f - T_b.

  • At standstill (s=1s = 1): sf=sb=1s_f = s_b = 1, so Tf=TbT_f = T_b and the net torque is zero. The motor is not self-starting.
  • If the rotor is started in either direction, the two torques become unequal. The backward field acts on the rotor at a high slip (2−s2 - s), so the rotor current it induces has a high frequency, is limited mainly by reactance and has a low power factor; the backward torque is therefore small. So Tf>TbT_f > T_b in the direction of rotation, and the motor keeps accelerating to near NsN_s.
  • At NsN_s (s=0s=0): Tf=0T_f = 0, but TbT_b is not zero (slip 2), so the net torque is slightly negative; the motor runs at a speed a little below NsN_s.
  T
  |   Tf              net T = Tf - Tb
  |   .--.            _.-'-._
  |  /    \          /       \
  +-/------\--------/---------\---> N
  -Ns  Tb   0      (start)     Ns

The net torque curve passes through zero at standstill and is positive at positive speeds (and negative at negative speeds).

✓ Answer checked by Claude Opus 5.5 (high effort)

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