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Double field revolving theory
Short answer
A pulsating flux is resolved into two equal rotating fluxes of half amplitude, rotating oppositely at synchronous speed. At standstill, their torques cancel, so the motor is not self-starting; once rotating, forward torque exceeds backward torque.
What do you understand by double field revolving theory? Explain it with the help of a neat diagram.
Double field revolving theory (DFRT)
A single-phase winding carrying alternating current produces a pulsating (alternating) flux along a fixed axis: . According to the double field revolving theory, this pulsating flux is equivalent to two rotating fluxes, each of constant magnitude , rotating at synchronous speed in opposite directions.
- : the forward-rotating component (in the direction of the rotor).
- : the backward-rotating component (in the opposite direction).
phi_f = phi_m/2 --> (anticlockwise)
\ /
phi_b \ / resultant = phi_m cos(wt)
= phi_m/2 X along fixed axis (pulsating)
(clockwise)
At every instant the components perpendicular to the winding axis cancel, and the components along the axis add, giving the pulsating flux .
Rotor behaviour
Each field induces rotor currents and produces its own torque. For a rotor speed in the forward direction:
- Slip with respect to the forward field:
- Slip with respect to the backward field:
The net torque is .
- At standstill (): , so and the net torque is zero. The motor is not self-starting.
- If the rotor is started in either direction, the two torques become unequal. The backward field acts on the rotor at a high slip (), so the rotor current it induces has a high frequency, is limited mainly by reactance and has a low power factor; the backward torque is therefore small. So in the direction of rotation, and the motor keeps accelerating to near .
- At (): , but is not zero (slip 2), so the net torque is slightly negative; the motor runs at a speed a little below .
T
| Tf net T = Tf - Tb
| .--. _.-'-._
| / \ / \
+-/------\--------/---------\---> N
-Ns Tb 0 (start) Ns
The net torque curve passes through zero at standstill and is positive at positive speeds (and negative at negative speeds).
✓ Answer checked by Claude Opus 5.5 (high effort)
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