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Double revolving field theory
Short answer
A pulsating field equals two half-magnitude fields rotating oppositely at synchronous speed. At standstill, forward and backward torques cancel, net torque zero; given initial rotation, forward torque dominates and motor runs. Thus not self-starting but works once started.
Using double revolving field theory, explain the working of a single phase induction motor (with a neat diagram).
A single-phase winding carrying a.c. produces a pulsating (alternating) field, φ = φ_m cos ωt, along a fixed axis. It does not rotate. The double revolving field theory says that such a pulsating field is equal to two rotating fields of half the magnitude, turning in opposite directions at synchronous speed.
Resolution of the pulsating flux
i.e. the sum of two vectors, each of length φ_m/2:
- forward field φ_f = φ_m/2, rotating at +N_s (say anticlockwise)
- backward field φ_b = φ_m/2, rotating at −N_s (clockwise)
ωt = 0 ωt = 90° ωt = 180°
ff and fb ff and fb point ff and fb both
both point opposite ways, at point the other
along +axis: 90° to the axis: way along the axis:
sum = φm sum = 0 sum = -φm
ff = fb = φm/2, turning in opposite directions;
resultant = φm cos ωt along the fixed axis
The components at right angles to the axis cancel at every instant, and the components along the axis add to give φ_m cos ωt.
Working of the motor
Let the rotor turn in the forward direction at speed N. The slip with respect to the forward field is s_f = (N_s − N)/N_s = s. The slip with respect to the backward field is
s_b = (N_s + N)/N_s = 2 − s
Each field induces rotor currents and develops its own torque, T_f (forward) and T_b (backward). The net torque is T = T_f − T_b.
| Condition | Slip f / b | Result |
|---|---|---|
| Standstill (s = 1) | 1 / 1 | T_f = T_b, so net torque is zero |
| Rotor started forward | s / 2 − s | T_f > T_b, net forward torque |
| Rotor near N_s (s → 0) | ~0 / ~2 | T_f large, T_b small |
Torque
|
| ffffff
| fffff f
| ffffff ********f
| fffffffffff **** *f
| fffffffffffffffffffffff **** *f
|f ******
--+b*------------------------*****------------------------*f> N
| ****** b
| b* **** bbbbbbbbbbbbbbbbbbbbbbb
| b* **** bbbbbbbbbbb
| b******** bbbbbb
| b bbbbb
| bbbbbb
|
-Ns 0 +Ns
f = Tf (forward field), b = Tb (backward field, acting in reverse)
* = net torque T = Tf - Tb: zero at N = 0, positive for forward
running, and zero again just below +Ns
The net torque is zero at standstill, so the single-phase induction motor has no starting torque. If the rotor is given a push in either direction, it keeps rotating in that direction, since the torque of the field rotating that way (T_f or T_b) becomes larger than the other. Near synchronous speed the backward torque is small, because the slip 2 − s for the backward field is near 2: the rotor current it causes is at nearly twice the supply frequency, lags heavily and gives little torque. The net torque falls to zero at a speed slightly below N_s, so the motor never reaches N_s.
✓ Answer checked by Claude Opus 5.5 (high effort)
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