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Output equation of three phase induction motor
Short answer
The output equation is Q = C0 D² L ns with C0 = 11 Bav ac Kw ×10⁻³, relating kVA input to stator bore diameter D, core length L, synchronous speed ns, and specific loadings Bav and ac, derived from emf and mmf expressions.
Derive the output equation for three phase induction motor.
The output equation relates the kVA input rating of a 3-phase induction motor to its main dimensions ( = stator bore diameter, = core length), its specific loadings (, ) and its synchronous speed .
Symbols
- = number of poles, = frequency, = synchronous speed (rps)
- = flux per pole (Wb), = turns per phase, = winding factor
- , = phase voltage and phase current
- = specific magnetic loading (Wb/m²), = specific electric loading (A/m)
Step 1: kVA input
Neglecting the small drop, :
Step 2: Induced emf
Step 3: Magnetic loading
Total flux around the gap is over area :
Step 4: Electric loading
Total stator conductors , each carrying :
Step 5: Substitute
So
is called the output coefficient. The kVA input is found from the rated shaft output:
Meaning of the result
- , so the volume of the active part is directly proportional to rating and inversely proportional to speed and specific loadings.
- Higher and give a smaller, cheaper machine, but power factor, temperature rise and overload capacity limit them.
- A high-speed motor is smaller than a low-speed motor of the same rating.
- Typical ranges: – Wb/m², – A/m, for a full-pitch, 60° phase-spread winding.
The product is then split into and using a chosen ratio (for example for good overall design) and a check on peripheral speed ( m/s for normal designs).
✓ Answer checked by Claude Sonnet 5.5
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