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Define RMF; torque-speed characteristics

Short answer

A rotating magnetic field has constant magnitude 1.5 phi_m and rotates at synchronous speed Ns = 120f/P. Torque-speed curve rises from starting torque at standstill to maximum at sm = R2/X2, then falls to zero at Ns; stable region is between maximum and Ns, with rated slip 2-5%.

Define rotating magnetic field in three phase induction motor. Explain the Torque-Speed (T-N) characteristics of three phase induction motor.

Rotating magnetic field (RMF)

A rotating magnetic field is a magnetic field of constant magnitude (1.5ϕm1.5\phi_m for a three-phase winding) whose axis rotates in space at synchronous speed Ns=120fPN_s = \frac{120f}{P} rpm. It is produced by feeding balanced three-phase currents to three windings displaced 120∘120^\circ in space.

Torque-speed (T-N) characteristics

The torque developed is

T=3ωs⋅sE22R2R22+(sX2)2T = \frac{3}{\omega_s}\cdot\frac{s E_2^2 R_2}{R_2^2 + (sX_2)^2}
 T
 |            Tmax
 |          _.-*-._
 |   Tst  /         \
 |    *--'            \
 |   /                  \
 |  /                     \
 +--+------+----------------+--> N
  N=0   N(Tmax)             Ns

Main points of the curve:

  1. Starting (N = 0, s = 1): the torque is the starting torque TstT_{st}. For a squirrel-cage motor it is about 1.5 to 2 times full-load torque.
  2. Between standstill and pull-out: the torque rises with speed, because the rotor reactance sX2sX_2 falls and the power factor improves, until it reaches the maximum (breakdown) torque at sm=R2X2s_m = \frac{R_2}{X_2}, where Tmax=3E222ωsX2T_{max} = \frac{3E_2^2}{2\omega_s X_2}.
  3. Stable region (s<sms < s_m): from TmaxT_{max} down to NsN_s the torque falls almost linearly with speed. The motor works here at rated load with slip of 2 to 5 %.
  4. At N=NsN = N_s (s=0s=0): the torque is zero.
  5. Unstable region (s>sms > s_m): if the load torque exceeds TmaxT_{max}, the speed falls and the torque falls too, so the motor stalls.

Increasing the rotor resistance moves sms_m toward standstill (the same TmaxT_{max}), and with R2=X2R_2 = X_2 the maximum torque occurs at starting. A fall of supply voltage reduces torque in proportion to V2V^2.

✓ Answer checked by Claude Opus 5.5 (high effort)

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