- 2078 Chaitra · 6 marks
DC shunt motor with open field circuit
Short answer
Flux collapses to residual, back EMF drops nearly to zero, armature current surges to V/R_a. On light load the motor over-speeds dangerously (runaway); on heavy load it may stall while drawing high current. This risks mechanical damage from centrifugal forces, overheating, sparking, and potential flashover.
A dc shunt motor is operating at a constant speed supplied with rated voltage. Due to an accident, the field terminal of the motor gets disconnected. What will happen on the motor performance? Discuss on the implications.
If the field circuit of a running DC shunt motor opens, the flux falls suddenly to the small residual flux. Since and , both speed and current change drastically.
What happens
- Flux collapses: drops to residual value, maybe 2-5% of normal.
- Back emf drops: at that instant speed cannot change (inertia), so falls almost to zero.
- Armature current rises sharply: approaches , many times the rated value, like a start without a starter.
- Torque and speed:
- With a light load, the large times the small still gives enough torque, so the motor accelerates rapidly. To build enough back emf with tiny flux, speed must rise to a very high value. The motor runs away (over-speeds).
- With a heavy load, the torque may be less than load torque. The motor slows or stalls while drawing a very large current.
Implications
- Mechanical damage: centrifugal forces at over-speed can throw out armature windings, damage the commutator and bearings, and burst the rotor.
- Electrical damage: very large armature current overheats the winding and insulation.
- Heavy sparking and flashover at the commutator due to large current and weak field (poor commutation).
- Supply disturbance: fuses/breakers trip; voltage dip affects other loads.
- Safety hazard to persons nearby and to the driven machine.
- Inductive kick: opening a highly inductive field can produce a high voltage arc at the break, damaging the field insulation.
Protection
- A three-point starter has its no-volt coil in series with the field, so a field break releases the handle and disconnects the motor.
- Field-failure relays, over-speed trips, and overload/over-current relays or circuit breakers.
- The field circuit should never contain a fuse or switch that can open it alone.
N, Ia
| ___ speed (runaway)
| _/
| _/ ___ armature current
| _/ _/
|___/___/__________________ time
^ field opens
✓ Answer checked by Claude Opus 5.5 (high effort)
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