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Stability: HS 202/65, joints J1 to J4

Short answer

With phi assumed 30°, lower-hemisphere stereonet analysis reveals toppling on J3 (dips 73° opposite face, >55° limit) and wedge failure along J1-J4 intersection (plunge 47.1° towards 260°, between phi and face apparent dip). Slope unstable, needs flattening/reinforcement.

Discuss the stability analysis based on the following data. HS = 202°/65°, F = 350°/27° [last digit unclear in the scan], J1 = 180°/81°, J2 = 78°/69°, J3 = 21°/73°, J4 = 293°/52°. [Figure: stereonet showing HS, F, J1, J2, J3, J4]

Method (lower-hemisphere stereonet, equal-angle): plot the great circle of the slope face and of each discontinuity, draw the friction circle of radius ϕ\phi, and mark intersections of great circles. Then apply the kinematic tests below.

Data (dip/dip direction)

HS 65/202; F 27/350; J1 81/180; J2 69/078; J3 73/021; J4 52/293. The friction angle is not given, so ϕ=30∘\phi = 30^\circ is assumed (typical for rock joints). (The last digit of F in the scan is unclear; 27∘27^\circ is used. As F dips into the hill at less than ϕ\phi, it does not affect the result.)

Single planes

Plane (dip/dip dir)Diff. of dip dir from slopeDaylights (ψp<ψf\psi_p<\psi_f)ψp>ϕ\psi_p>\phiResult
F (27/350)148°yesnoSafe
J1 (81/180)22°noyesSafe
J2 (69/078)124°noyesSafe
J3 (73/021)179°noyesToppling
J4 (52/293)91°yesyesSafe

Intersections

PairIntersection plunge/trendFace apparent dip along trendResult
F x J14.7° / 269°39.7°Stable (plunge below ϕ\phi)
J1 x J447.1° / 260°48.5°Wedge failure

(The other 8 intersections plunge into the hill, away from the face, and cannot slide.)

Result

  • J3 (73/021) dips into the hill almost exactly opposite to the face (the face dips towards 202°, so the opposite direction is 022°). Its dip of 73∘73^\circ is more than 90∘−65∘+30∘=55∘90^\circ - 65^\circ + 30^\circ = 55^\circ, so toppling failure is possible.
  • J1 strikes nearly parallel to the face but dips 81∘81^\circ, steeper than the face, so it does not daylight.
  • F (27°) dips into the hill and is below ϕ\phi; J2 and J4 do not daylight individually.
  • The intersection J1 x J4 plunges about 47.1° towards 260°, between ϕ\phi and the face apparent dip (48.5°), so wedge failure is also possible.

Conclusion: the slope is unstable. The main modes are toppling along J3 and wedge sliding along the J1-J4 intersection. Reduce the slope angle, remove the potential wedge, and use bolts or anchors and drainage.

✓ Answer checked by Claude Opus 5.5 (high effort)

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