- Practice · 8 marks
Laminar flow between fixed parallel plates
Short answer
Velocity distribution u = -(1/(2μ))(dp/dx)(hy - y^2). Shear stress τ = -(dp/dx)(h/2 - y), linear. Maximum velocity u_max = -(h^2/(8μ))(dp/dx). Average velocity ū = (2/3)u_max = -(h^2/(12μ))(dp/dx). Discharge per unit width q = -(h^3/(12μ))(dp/dx). Pressure drop Δp = (12μūL)/h^2.
Derive the expressions for velocity distribution, shear stress distribution, maximum velocity, average velocity and discharge per unit width for steady laminar flow of a viscous incompressible fluid between two fixed parallel plates a distance apart. Also obtain the pressure drop in a length .
Assumptions
Steady, laminar, fully developed flow of a Newtonian incompressible fluid between two fixed wide plates, gap . Flow is in the -direction; is measured from the lower plate. There is no body force effect other than hydrostatic, and is constant.
y ^ --------------------------- upper plate (u = 0)
| ______
| h / \ u(y)
| \________/
+---------------------------> x lower plate (u = 0)
Force balance on an element
Consider a fluid element of length , thickness and unit width. Net force in is zero:
With :
Velocity distribution
Integrating twice, . Boundary conditions at and at give and .
The profile is parabolic. The pressure falls in the flow direction, so and .
Shear stress distribution
It is zero at the centre line and maximum at the walls: (linear variation).
Maximum velocity
At :
Discharge and average velocity
Pressure drop
For a length , :
The head loss is .
✓ Answer checked by Claude Opus 5.5 (high effort)
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