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Speed of sound and Mach number

Short answer

Mach number Ma = V/a, the ratio of flow velocity to local speed of sound. For an ideal gas, the isentropic wave speed is a = sqrt(kRT). Flows are classified: Ma<0.3 incompressible, 0.3-0.8 subsonic, 0.8-1.2 transonic, 1.2-5 supersonic, >5 hypersonic. Flow may be treated as incompressible for Ma < 0.3 where density change is under about 5%.

Define Mach number. Derive an expression for the velocity of a sound wave (small pressure disturbance) in a compressible fluid and show that for an ideal gas it is a=kRTa = \sqrt{kRT}. Classify compressible flow according to Mach number, and state when a flow may be treated as incompressible.

Mach number

Ma=VaMa = \frac{V}{a}

where VV is the flow velocity and aa is the local speed of sound. It measures the importance of compressibility: the ratio of inertia force to elastic force.

Speed of sound

Consider a small pressure wave moving at speed aa into still fluid of density ρ\rho and pressure pp. In a frame fixed to the wave, the fluid approaches at speed aa and leaves at a−dVa - dV, with properties ρ+dρ\rho + d\rho and p+dpp + dp.

   still fluid         wave        disturbed fluid
   p, rho, V = 0  -->  |  a  |    p+dp, rho+drho, dV

Continuity: ρa=(ρ+dρ)(a−dV)\rho a = (\rho + d\rho)(a - dV). Neglecting the product dρ dVd\rho\,dV:

dV=adρρdV = a\frac{d\rho}{\rho}

Momentum: p−(p+dp)=ρa [(a−dV)−a]p - (p + dp) = \rho a\,[(a - dV) - a], so dp=ρa dVdp = \rho a\,dV.

Eliminating dVdV:

a2=dpdρ⇒a=dpdρ=Evρa^2 = \frac{dp}{d\rho} \quad \Rightarrow \quad a = \sqrt{\frac{dp}{d\rho}} = \sqrt{\frac{E_v}{\rho}}

where EvE_v is the bulk modulus. The small wave is nearly reversible and adiabatic, so the process is isentropic: p/ρk=p/\rho^k = constant, which gives dp/dρ=kp/ρdp/d\rho = kp/\rho. With p=ρRTp = \rho RT:

a=kRTa = \sqrt{kRT}

For air, k=1.4k = 1.4, R=287 J/kg KR = 287\ \text{J/kg K}, so a=20.05Ta = 20.05\sqrt{T} m/s (343 m/s at 20 °C).

Classification of flow

Mach numberFlow regime
Ma<0.3Ma < 0.3Incompressible
0.3<Ma<0.80.3 < Ma < 0.8Subsonic compressible
0.8<Ma<1.20.8 < Ma < 1.2Transonic
Ma=1Ma = 1Sonic
1.2<Ma<51.2 < Ma < 5Supersonic
Ma>5Ma > 5Hypersonic

Incompressible treatment

For Ma<0.3Ma < 0.3 the density change in the flow is less than about 5%, so the flow can be treated as incompressible. Above this value compressibility effects must be included.

✓ Answer checked by Claude Opus 5.5 (high effort)

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