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Variation of hydraulic radius with depth
Short answer
For a rectangular channel, R = by/(b+2y). When b >> y, R approx y (wide channel). When y >> b, R approx b/2 (deep gorge).
How does hydraulic radius vary for wide and narrow (deep) rectangular channels? Show that hydraulic radius is equal to depth of flow for a wide rectangular channel and half of the bed width for deep gorges.
Hydraulic radius is the ratio of flow area to wetted perimeter. For a rectangle of bed width and depth :
Variation
- For a given , increases with from zero (at ) and approaches the limit for very large .
- For a given , increases with and approaches for very large .
| Channel | Condition | |
|---|---|---|
| Wide, shallow | ||
| Narrow, deep (gorge) |
Wide rectangular channel
Divide numerator and denominator by :
For , , so
The side walls contribute negligible wetted perimeter, so and .
Deep narrow channel (gorge)
Divide numerator and denominator by :
For , , so
Here the bed is small compared with the two deep walls, so and .
wide: R ~ y gorge: R ~ b/2
~~~~~~~~~~~~~~~ |~~|
|_____________| | | y >> b
✓ Answer checked by Claude Opus 5.5 (high effort)
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