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Variation of hydraulic radius with depth

Short answer

For a rectangular channel, R = by/(b+2y). When b >> y, R approx y (wide channel). When y >> b, R approx b/2 (deep gorge).

How does hydraulic radius vary for wide and narrow (deep) rectangular channels? Show that hydraulic radius is equal to depth of flow for a wide rectangular channel and half of the bed width for deep gorges.

Hydraulic radius R=APR=\dfrac{A}{P} is the ratio of flow area to wetted perimeter. For a rectangle of bed width bb and depth yy:

A=by,P=b+2y,R=byb+2yA=by,\qquad P=b+2y,\qquad R=\frac{by}{b+2y}

Variation

  • For a given bb, RR increases with yy from zero (at y=0y=0) and approaches the limit b/2b/2 for very large yy.
  • For a given yy, RR increases with bb and approaches yy for very large bb.
ChannelConditionRR
Wide, shallowb≫yb\gg y≈y\approx y
Narrow, deep (gorge)y≫by\gg b≈b/2\approx b/2

Wide rectangular channel

Divide numerator and denominator by bb:

R=y1+2y/bR=\frac{y}{1+2y/b}

For b≫yb\gg y, 2y/b→02y/b\to0, so

R≈yR\approx y

The side walls contribute negligible wetted perimeter, so P≈bP\approx b and R=by/b=yR=by/b=y.

Deep narrow channel (gorge)

Divide numerator and denominator by yy:

R=bb/y+2R=\frac{b}{b/y+2}

For y≫by\gg b, b/y→0b/y\to0, so

R≈b2R\approx\frac{b}{2}

Here the bed is small compared with the two deep walls, so P≈2yP\approx2y and R=by/2y=b/2R=by/2y=b/2.

 wide: R ~ y            gorge: R ~ b/2
 ~~~~~~~~~~~~~~~        |~~|
 |_____________|        |  |  y >> b

✓ Answer checked by Claude Opus 5.5 (high effort)

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