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Mixing length, Hagen-Poiseuille, Nikuradse, Colebrook

Short answer

Prandtl's mixing length theory gives τ_t = ρ(κy)²(du/dy)² and log laws. Hagen-Poiseuille: Q = πD⁴Δp/(128μL), f = 64/Re. Nikuradse's sand-roughened pipe experiments identified smooth, transition, and fully rough regimes; the Colebrook-White equation 1/√f = -2 log₁₀(k/(3.7D) + 2.51/(Re√f)) unifies smooth and rough friction.

Describe with appropriate expressions (a) Prandtl's mixing length theory (b) Hagen-Poiseuille equation (c) Nikuradse's experiments and (d) Colebrook-White equation.

(a) Prandtl's mixing length theory

Turbulent eddies move lumps of fluid across the layers; a lump keeps its identity over the mixing length ll before mixing. The velocity fluctuations are u′≈v′≈l dudyu' \approx v' \approx l\,\dfrac{du}{dy}, so the turbulent shear stress is

τt=−ρu′v′‾=ρ l2(dudy)2,l=κy, κ≈0.4\tau_t = -\rho\overline{u'v'} = \rho\,l^2\left(\frac{du}{dy}\right)^2, \qquad l = \kappa y,\ \kappa \approx 0.4

The total stress is τ=μdudy+ρl2(dudy)2\tau = \mu\dfrac{du}{dy} + \rho l^2\left(\dfrac{du}{dy}\right)^2. For constant τ=τ0\tau = \tau_0 near the wall, it leads to the logarithmic velocity law uu∗=5.75log⁡10u∗yν+5.5\dfrac{u}{u_*} = 5.75\log_{10}\dfrac{u_*y}{\nu} + 5.5 (smooth) and 5.75log⁡10yk+8.55.75\log_{10}\dfrac{y}{k} + 8.5 (rough), where u∗=τ0/ρu_* = \sqrt{\tau_0/\rho}.

(b) Hagen-Poiseuille equation

For steady laminar flow in a circular pipe of diameter DD and length LL the discharge and head loss are

Q=πD4 Δp128 μL,hf=32μLVγD2Q = \frac{\pi D^4\,\Delta p}{128\,\mu L}, \qquad h_f = \frac{32\mu L V}{\gamma D^2}

The velocity is parabolic, u=Δp4μL(R2−r2)u = \dfrac{\Delta p}{4\mu L}(R^2 - r^2), with umax=2Vu_{max} = 2V. Comparing with Darcy-Weisbach gives f=64/Ref = 64/Re. It is valid for Re<2000Re < 2000.

(c) Nikuradse's experiments

Nikuradse (1933) measured head loss in pipes artificially roughened with uniform sand grains of size kk, for relative roughness k/Dk/D from 1/30 to 1/1014 and ReRe from 10310^3 to 10610^6. Plotting log⁡f\log f against log⁡Re\log Re he found:

  • Laminar flow: all pipes lie on f=64/Ref = 64/Re, independent of roughness.
  • Smooth turbulent: ff follows Blasius/Prandtl smooth curve, depends on ReRe only.
  • Transition: ff depends on both ReRe and k/Dk/D.
  • Fully rough: ff becomes constant for given k/Dk/D, depends on k/Dk/D only; 1f=2log⁡10Dk+1.14\dfrac{1}{\sqrt f} = 2\log_{10}\dfrac{D}{k} + 1.14.

(d) Colebrook-White equation

For commercial pipes, Colebrook and White combined the smooth and rough laws into one transition formula:

1f=−2log⁡10(k3.7D+2.51Ref)\frac{1}{\sqrt f} = -2\log_{10}\left(\frac{k}{3.7D} + \frac{2.51}{Re\sqrt f}\right)
  • When k→0k \to 0 (smooth): 1f=2log⁡10(Ref)−0.8\dfrac{1}{\sqrt f} = 2\log_{10}(Re\sqrt f) - 0.8.
  • When Re→∞Re \to \infty (rough): 1f=2log⁡10Dk+1.14\dfrac{1}{\sqrt f} = 2\log_{10}\dfrac{D}{k} + 1.14. The equation is implicit in ff and is solved by iteration; it is the basis of the Moody chart.

✓ Answer checked by Claude Sonnet 5.5

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