- Practice · 6 marks
Thermocouple laws and emf calculation
Short answer
Thermocouple laws: homogeneous circuit, intermediate metals, intermediate temperatures. (a) E_100,300 = E_0,300 - E_0,100 = 12.209 - 4.096 = 8.113 mV. (b) Referred to 0°C: E_0,T = 7.5 + 1.203 = 8.703 mV; linearly interpolating between 200°C (8.138 mV) and 300°C (12.209 mV) gives T ≈ 213.9°C.
State the laws of thermocouples. A chromel-alumel thermocouple gives the following emf against a 0 C reference: 30 C, 1.203 mV; 100 C, 4.096 mV; 200 C, 8.138 mV; 300 C, 12.209 mV. Find (a) the emf when the junctions are at 300 C and 100 C, and (b) the hot-junction temperature if an instrument whose cold junction is at 30 C reads 7.5 mV (use linear interpolation).
A thermocouple produces an emf when two dissimilar metals joined at two junctions are at different temperatures (Seebeck effect).
Laws of thermocouples
- Law of homogeneous circuit: a thermoelectric current cannot be sustained in a circuit of a single homogeneous metal by heat alone, however the section varies. A temperature gradient in a uniform wire adds no emf.
- Law of intermediate metals: a third metal inserted in the circuit (e.g. the voltmeter leads) adds no net emf if its two junctions are at the same temperature.
- Law of intermediate temperatures: if the emf between junction temperatures and is and between and is , then . This lets tables with a 0 C reference be used for any cold junction.
(a) Junctions at 300 C and 100 C
(b) Hot junction temperature
The instrument reads 7.5 mV with cold junction at 30 C. Referred to 0 C:
This lies between 200 C (8.138 mV) and 300 C (12.209 mV).
Answer: (a) 8.113 mV; (b) C.
✓ Answer checked by Claude Opus 5.5 (high effort)
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