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Ferranti effect and skin effect

Short answer

Ferranti effect: receiving-end voltage exceeds sending-end voltage under no-load/light-load due to line capacitance charging current flowing through series inductance. Skin effect: AC current concentrates near conductor surface because inner filaments link more flux, raising effective resistance; increases with frequency and conductor size.

Briefly explain Ferranti effect and skin effect.

Ferranti effect

The Ferranti effect is the rise of receiving-end voltage above the sending-end voltage when a long or medium line is on no load or very light load.

  • At light load, the line's shunt capacitance draws a charging current ICI_C that leads the voltage by 90∘90^\circ.
  • This current flows through the series inductance and produces a drop jXLICjX_L I_C, which points opposite to VRV_R (since jXL⋅jI=−XLIjX_L \cdot jI = -X_L I), so VS=VR−XLICV_S = V_R - X_L I_C is smaller than VRV_R.
  • For a nominal-π\pi line at no load (neglecting RR, with LL and CC the total line values), VS=AVRV_S = A V_R with A=1−ω2LC/2A = 1 - \omega^2 LC/2, so VR=VS/(1−ω2LC/2)>VSV_R = V_S/(1-\omega^2LC/2) > V_S.
  • The rise is roughly proportional to the square of the line length and is large for EHV lines (about 5–10 % at 400 km).
        jXL*Ic
   Vr --------> Vs  (Vs shorter than Vr)
   ^
   | Ic (leads Vr by 90 deg)

Remedy: shunt reactors at the receiving end, or keeping some load connected.

Skin effect

The skin effect is the tendency of alternating current to crowd towards the outer surface of a conductor instead of spreading uniformly over its cross-section.

  • The inner filaments of a conductor link more flux than the outer ones, so they have higher inductive reactance. Current therefore takes the outer, lower-reactance path.
  • The effective area carrying current falls, so the AC resistance is greater than the DC resistance.
  • It increases with frequency, conductor diameter, permeability and conductivity. At 50 Hz it is small for normal conductors (a few percent) but is not negligible for large conductors.
  • It is absent for DC.

Reduction: use stranded conductors (ACSR) or hollow/tubular conductors; in ACSR the steel core sits at the centre, where little current flows anyway.

✓ Answer checked by Claude Opus 5.5 (high effort)

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