- 2074 Bhadra · 8 marks
Reducing Ferranti effect mathematically
Short answer
Ferranti effect is reduced by shunt reactors, which absorb charging current. With a reactor XL at the receiving end, Vr/Vs=1/[cos βl+(Zc/XL) sin βl]; selecting XL=Zc cot(βl/2) makes Vr=Vs.
How the Ferranti effect can be reduced in over voltage issues? Explain mathematically.
The Ferranti effect is the rise of receiving-end voltage above the sending-end voltage on a long line at no load or light load. The line's charging current flows through its series inductance and raises the voltage along the line. It is a main cause of temporary overvoltage.
Mathematical explanation
For a lossless line of length , phase constant and surge impedance :
At no load :
At 50 Hz, per 100 km. For example, a 400 km line with mH/km and nF/km gives rad and . A 1500 km line () gives an infinite voltage.
Reduction by shunt reactor compensation
Connect a shunt reactor at the receiving end. At no load, the reactor current is
Substituting:
The extra positive term in the denominator reduces . For :
Physically, the reactor draws a lagging current that cancels part of the line's leading charging current. A smaller net current flows through the series inductance, so the voltage rise is smaller.
Other methods
- Shunt reactors at the ends and at intermediate stations; switched or controlled reactors for varying load.
- Static VAR compensators (SVC) and STATCOMs, which absorb reactive power under light load.
- Series capacitors are not used for this. They reduce the effective electrical length for power transfer but do not cure the no-load rise.
- Sectionalising long lines with intermediate substations, so that of each section is small.
- Generator under-excitation (absorbing VArs), within stability limits.
- Proper switching sequence: energise the line from the stronger end and connect the reactors before or with the line.
✓ Answer checked by Claude Opus 5.5 (high effort)
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