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GMR of 4-strand conductor in terms of r

Short answer

GMR is 1.723 times the strand radius r.

Calculate the GMR to calculate inductance of the stranded conductor shown in figure below in terms of radius 'r' of an individual strand. [Figure: four identical touching strands arranged in a 2 × 2 square.]

The GMR of an nn-strand conductor is the n2n^2-th root of the product of all inter-strand distances, with each strand's self-distance r′=0.7788rr' = 0.7788r.

     (1)   (2)
     (3)   (4)
  side = 2r, diagonal = 2(sqrt2)r

Distances

PairDistance
1-2, 1-3, 2-4, 3-42r2r
1-4, 2-322r2\sqrt2 r

By symmetry every strand sees the same set: r′r', 2r2r, 2r2r, 22r2\sqrt2 r.

GMR

Ds=[(r′⋅2r⋅2r⋅22r)4]1/16=(r′×82 r3)1/4=(0.7788×11.314)1/4r=(8.811)1/4r=1.7229 r\begin{aligned} D_s &= \left[(r' \cdot 2r \cdot 2r \cdot 2\sqrt2 r)^4\right]^{1/16} = \left(r' \times 8\sqrt2\, r^3\right)^{1/4} \\ &= \left(0.7788 \times 11.314\right)^{1/4} r = (8.811)^{1/4} r \\ &= 1.7229\,r \end{aligned}

Answer: GMR =1.723r= 1.723r (for capacitance, using rr instead of r′r', it is 1.834r1.834r).

✓ Answer checked by Claude Opus 5.5 (high effort)

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