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Commutative property of CT LTI systems

Short answer

Convolution is commutative: x(t)*h(t) = h(t)*x(t). Proof: substitute λ=t-τ in the convolution integral, yielding ∫ x(τ)h(t-τ)dτ = ∫ h(λ)x(t-λ)dλ. So the order of systems can be swapped.

State and prove commutative property of continuous time LTI system.

Statement: Convolution of continuous-time signals is commutative:

x(t)∗h(t)=h(t)∗x(t)x(t) * h(t) = h(t) * x(t)

For LTI systems, this means the output is the same whether the input is x(t)x(t) applied to a system with impulse response h(t)h(t), or h(t)h(t) applied to a system with impulse response x(t)x(t).

Proof:

x(t)∗h(t)=∫−∞∞x(τ) h(t−τ) dτx(t) * h(t) = \int_{-\infty}^{\infty} x(\tau)\,h(t - \tau)\,d\tau

Substitute λ=t−τ\lambda = t - \tau, so τ=t−λ\tau = t - \lambda and dτ=−dλd\tau = -d\lambda. When τ→−∞\tau \to -\infty, λ→∞\lambda \to \infty; when τ→∞\tau \to \infty, λ→−∞\lambda \to -\infty:

x(t)∗h(t)=∫∞−∞x(t−λ) h(λ) (−dλ)=∫−∞∞h(λ) x(t−λ) dλ=h(t)∗x(t)\begin{aligned} x(t) * h(t) &= \int_{\infty}^{-\infty} x(t - \lambda)\,h(\lambda)\,(-d\lambda) \\ &= \int_{-\infty}^{\infty} h(\lambda)\,x(t - \lambda)\,d\lambda = h(t) * x(t) \end{aligned}

■\blacksquare

x(t) --> [ h(t) ] --> y(t)   ==   h(t) --> [ x(t) ] --> y(t)

Use: we can flip whichever signal is simpler when evaluating the integral; and for cascaded LTI systems, the order of the systems can be swapped.

✓ Answer checked by Claude Opus 5.5 (high effort)

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