- 2076 Baisakh · 4 marks
Behaviour of x[n] = cαⁿ
Short answer
For x[n]=cα^n with real c,α (c>0): α>1 grows unbounded; 0<α<1 decays; α=1 constant; -1<α<0 alternates sign and decays; α<-1 alternates and grows; α=-1 alternates ±c. A negative c flips the sequence.
Explain the behaviour of discrete time complex exponential x[n] = cαⁿ where c and α are real.
With and both real, is a real exponential sequence. Its shape depends on the value of (take ):
| Value of | Behaviour of |
|---|---|
| Grows exponentially with (unbounded) | |
| Constant, | |
| Decays exponentially towards 0 | |
| Alternates in sign and decays | |
| Alternates between and | |
| Alternates in sign and grows |
For negative , is positive for even and negative for odd , giving the alternating pattern. A negative simply flips the whole sequence.
0 < alpha < 1: decays
o
|
| o
| | o o
--+--+--+--+--o-> n
0 1 2 3 4
alpha > 1: grows
o
|
o |
o | |
o o | | |
--+--+--+--+--+-> n
0 1 2 3 4
-1 < alpha < 0: alternates, decays
o
|
|
| o
--+--+--+--+--o-> n
| o
o
0 1 2 3 4
alpha < -1: alternates, grows
o
|
o |
--+--+--+--+-> n
| |
o |
|
o
0 1 2 3
Examples: decays (used for stable system impulse responses); oscillates and decays; grows (unstable).
✓ Answer checked by Claude Opus 5.5 (high effort)
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