- 2076 Bhadra · 8 marks
Exponential FS coefficients; Gibbs phenomenon
Short answer
The coefficient is a_k = (1/T) ∫_T x(t) e^{-j k ω0 t} dt. Gibbs phenomenon: truncating the series for a signal with a jump causes ripples near the discontinuity with a fixed overshoot of about 9% of the jump height, which does not vanish as more terms are added, though the ripples narrow.
Derive the expression to compute Fourier series coefficients of exponential Fourier series. Explain Gibbs phenomenon.
Exponential Fourier series coefficients
A periodic signal with period and is written as
Multiply both sides by and integrate over one period :
For :
For the integral is . Therefore
- is the dc value.
- is complex: is the magnitude spectrum and the phase spectrum.
- For real , .
Example: a square wave of height 1 for in period gives and .
Gibbs phenomenon
When a signal with a jump discontinuity (e.g. a square wave) is approximated by a finite number of Fourier terms,
the partial sum shows ripples near the discontinuity, with an overshoot of about 9% of the jump height on each side of it.
Key features:
- As increases, the ripples become narrower and crowd closer to the discontinuity, but the peak overshoot does not decrease; it stays at about 9% of the jump (about 1.09 times for a unit jump).
- At the discontinuity itself, the series converges to the midpoint .
- The energy of the error as (mean-square convergence), because the area under the ripples shrinks.
- It was explained by J. W. Gibbs (1899) after Michelson noticed the overshoot in a mechanical harmonic analyser.
x_N(t) near a jump (square wave)
overshoot ~9%
_/\_/\/\/\________
|
| finite N ripples
______|
\/\/\
^ jump at t = T1
Practical meaning: truncating a Fourier series (or ideal filtering, which cuts off high harmonics) produces ringing near sharp edges; window functions are used to reduce it.
✓ Answer checked by Claude Opus 5.5 (high effort)
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