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Exponential FS coefficients and existence

Short answer

The exponential Fourier series coefficient is a_k = (1/T) ∫_T x(t) e^{-j k ω0 t} dt. Existence requires Dirichlet conditions: absolute integrability, finite maxima/minima, and finite discontinuities per period. For example, 1/t violates absolute integrability, while a square wave satisfies all conditions.

Derive the expression of Fourier Series Coefficient in exponential form for Continuous time periodic signal. Describe the condition for existence of Fourier series with suitable examples.

Exponential Fourier series coefficients

Let x(t)x(t) be periodic with period TT, ω0=2π/T\omega_0 = 2\pi/T. It is expressed as a sum of harmonically related complex exponentials (synthesis equation):

x(t)=∑k=−∞∞akejkω0tx(t) = \sum_{k=-\infty}^{\infty}a_k e^{jk\omega_0 t}

Multiply both sides by e−jnω0te^{-jn\omega_0 t} and integrate over one period:

∫0Tx(t)e−jnω0tdt=∑k=−∞∞ak∫0Tej(k−n)ω0tdt\int_0^T x(t)e^{-jn\omega_0 t}dt = \sum_{k=-\infty}^{\infty}a_k\int_0^T e^{j(k-n)\omega_0 t}dt

The right-hand integral:

∫0Tej(k−n)ω0tdt=[ej(k−n)ω0tj(k−n)ω0]0T=ej(k−n)2π−1j(k−n)ω0=0(k≠n)\int_0^T e^{j(k-n)\omega_0 t}dt = \left[\frac{e^{j(k-n)\omega_0 t}}{j(k-n)\omega_0}\right]_0^T = \frac{e^{j(k-n)2\pi} - 1}{j(k-n)\omega_0} = 0 \quad (k \ne n)

and equals TT when k=nk = n. Only the k=nk = n term remains:

∫0Tx(t)e−jnω0tdt=anT\int_0^T x(t)e^{-jn\omega_0 t}dt = a_n T ak=1T∫Tx(t)e−jkω0tdta_k = \frac{1}{T}\int_T x(t)e^{-jk\omega_0 t}dt

This is the analysis equation. a0=1T∫Tx(t)dta_0 = \frac{1}{T}\int_T x(t)dt is the average value, and ∣ak∣|a_k|, ∠ak\angle a_k give the magnitude and phase spectra.

Conditions for existence (Dirichlet conditions)

Over one period:

  1. Absolutely integrable: ∫T∣x(t)∣dt<∞\int_T|x(t)|dt < \infty.
    • Violated by x(t)=1/tx(t) = 1/t on 0<t≤10 < t \le 1 (period 1): ∫01dt/t=∞\int_0^1 dt/t = \infty.
  2. Finite number of maxima and minima in a period.
    • Violated by x(t)=sin⁡(2π/t)x(t) = \sin(2\pi/t) on 0<t≤10 < t \le 1: it oscillates infinitely often near t=0t = 0.
  3. Finite number of discontinuities, each of finite size, in a period.
    • Violated by a staircase that steps down by half on [0,12),[12,34),[34,78),…[0, \frac12), [\frac12, \frac34), [\frac34, \frac78), \dots: infinitely many jumps in one period.

A signal that satisfies them: a square wave has two finite jumps per period, is bounded and has no oscillations, so its Fourier series exists; it converges to the midpoint value at each jump.

✓ Answer checked by Claude Opus 5.5 (high effort)

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