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Seepage and superficial velocity relation

Short answer

Superficial velocity v = Q/A is based on gross area. Seepage velocity v_s is the actual average velocity in the voids: v_s = v/n, where n is porosity. Because n<1, v_s > v. In terms of void ratio, v_s = v(1+e)/e.

Establish the relationship between seepage velocity and superficial velocity.

Superficial (discharge) velocity vv is based on the total area; seepage velocity vsv_s is the real velocity in the voids.

Derivation

Consider a soil of gross cross-section AA and length LL. Let AvA_v be the area of voids on the cross-section and VvV_v, VV the volumes of voids and total.

n=VvV=AvLAL=AvAn = \frac{V_v}{V} = \frac{A_v L}{A L} = \frac{A_v}{A}

Let the discharge be QQ. It passes through the gross area AA at velocity vv and through the void area AvA_v at velocity vsv_s:

Q=vA=vsAvQ = v A = v_s A_v vs=v AAv=vnv_s = v\,\frac{A}{A_v} = \frac{v}{n}

Since v=kiv = k i:

vs=k inv_s = \frac{k\,i}{n}

Since n<1n<1, vs>vv_s > v. In terms of void ratio, n=e1+en = \dfrac{e}{1+e} so vs=v 1+eev_s = v\,\dfrac{1+e}{e}.

✓ Answer checked by Claude Opus 5.5 (high effort)

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