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White noise: relation between PSDF and AC function

Short answer

White noise is an idealization with constant power spectral density N0/2 over all frequencies. By the Wiener–Khinchin theorem, the autocorrelation function is the inverse Fourier transform of the PSD, giving R(τ) = (N0/2)δ(τ). This impulse autocorrelation means any two distinct noise samples are uncorrelated.

Define white noise. Establish relation between psdf and the AC function of a white noise.

White noise

White noise is an idealised random noise whose power spectral density is flat (constant) over all frequencies, like white light containing all colours. Thermal and shot noise are nearly white up to very high frequencies (∼1012\sim 10^{12} Hz), so the model is accurate for any practical receiver bandwidth. It is usually also assumed Gaussian, zero-mean (AWGN).

Relation between PSDF and AC function

By the Wiener–Khinchin theorem, PSD and autocorrelation are a Fourier transform pair:

S(f)=∫−∞∞R(τ)e−j2πfτdτ,R(τ)=∫−∞∞S(f)ej2πfτdfS(f)=\int_{-\infty}^{\infty}R(\tau)e^{-j2\pi f\tau}d\tau,\qquad R(\tau)=\int_{-\infty}^{\infty}S(f)e^{j2\pi f\tau}df

PSD (two-sided):

SW(f)=N02for all fS_W(f)=\frac{N_0}{2}\quad\text{for all } f

where N0=kTeN_0=kT_e (W/Hz), kk = Boltzmann constant and TeT_e = equivalent noise temperature.

Autocorrelation (inverse Fourier transform of PSD, using F−1{1}=δ(τ)\mathcal{F}^{-1}\{1\}=\delta(\tau)):

RW(τ)=∫−∞∞N02ej2πfτdf=N02 δ(τ)R_W(\tau)=\int_{-\infty}^{\infty}\frac{N_0}{2}e^{j2\pi f\tau}df=\frac{N_0}{2}\,\delta(\tau)
   S_W(f)                      R_W(tau)
     |                             ^  (N0/2) delta
 N0/2+-----------------            |
     |                             |
 ----+-----------------> f   ------+------> tau
     0                             0

Meaning: RW(τ)=0R_W(\tau)=0 for every τ≠0\tau\ne0, so any two samples of white noise, however close, are uncorrelated (and independent if Gaussian). The total power RW(0)=∫SW(f)dfR_W(0)=\int S_W(f)df is infinite, which is why white noise is only a model; after any filter with finite bandwidth the power becomes finite.

✓ Answer checked by Claude Opus 5.5 (high effort)

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