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Autocorrelation properties; AC of white noise

Short answer

Autocorrelation is even: R(-τ)=R(τ); R(0) equals average power; |R(τ)| ≤ R(0). White noise has a constant power spectral density N0/2, and its autocorrelation function is (N0/2) δ(τ), indicating uncorrelated samples at any non-zero lag.

List out any three properties of autocorrelation (AC) function. Mention the autocorrelation function of white noise.

Properties of the autocorrelation function

The autocorrelation (AC) function measures how similar a signal is to a time-shifted copy of itself. For a power signal or a wide-sense stationary (WSS) random process X(t)X(t):

RX(τ)=lim⁡T→∞1T∫−T/2T/2x(t) x(t+τ) dtorRX(τ)=E[X(t)X(t+τ)]R_X(\tau)=\lim_{T\to\infty}\frac{1}{T}\int_{-T/2}^{T/2}x(t)\,x(t+\tau)\,dt \quad\text{or}\quad R_X(\tau)=E[X(t)X(t+\tau)]

For an energy signal, Rg(τ)=∫−∞∞g(t)g(t+τ) dtR_g(\tau)=\int_{-\infty}^{\infty}g(t)g(t+\tau)\,dt.

Important properties (any three answer the question):

  1. Even symmetry: RX(−τ)=RX(τ)R_X(-\tau)=R_X(\tau).
  2. Value at origin = mean-square value (power): RX(0)=E[X2(t)]=PR_X(0)=E[X^2(t)]=P (for an energy signal, Rg(0)=ER_g(0)=E).
  3. Maximum at origin: ∣RX(τ)∣≤RX(0)\lvert R_X(\tau)\rvert\le R_X(0) for all τ\tau.
  4. Fourier pair with PSD (Wiener–Khinchin): SX(f)=∫−∞∞RX(τ)e−j2πfτdτS_X(f)=\int_{-\infty}^{\infty}R_X(\tau)e^{-j2\pi f\tau}d\tau and RX(τ)=∫−∞∞SX(f)ej2πfτdfR_X(\tau)=\int_{-\infty}^{\infty}S_X(f)e^{j2\pi f\tau}df.
  5. Periodicity: if x(t)x(t) is periodic with period T0T_0, RX(τ)R_X(\tau) is also periodic with T0T_0.
  6. DC component: if X(t)X(t) has mean mm and no periodic part, RX(τ)→m2R_X(\tau)\to m^2 as τ→∞\tau\to\infty.

Autocorrelation function of white noise

White noise is an idealised random noise whose power spectral density is flat (constant) over all frequencies, like white light containing all colours. Thermal and shot noise are nearly white up to very high frequencies (∼1012\sim 10^{12} Hz), so the model is accurate for any practical receiver bandwidth. It is usually also assumed Gaussian, zero-mean (AWGN).

PSD (two-sided):

SW(f)=N02for all fS_W(f)=\frac{N_0}{2}\quad\text{for all } f

where N0=kTeN_0=kT_e (W/Hz), kk = Boltzmann constant and TeT_e = equivalent noise temperature.

Autocorrelation (inverse Fourier transform of PSD, using F−1{1}=δ(τ)\mathcal{F}^{-1}\{1\}=\delta(\tau)):

RW(τ)=∫−∞∞N02ej2πfτdf=N02 δ(τ)R_W(\tau)=\int_{-\infty}^{\infty}\frac{N_0}{2}e^{j2\pi f\tau}df=\frac{N_0}{2}\,\delta(\tau)
   S_W(f)                      R_W(tau)
     |                             ^  (N0/2) delta
 N0/2+-----------------            |
     |                             |
 ----+-----------------> f   ------+------> tau
     0                             0

Meaning: RW(τ)=0R_W(\tau)=0 for every τ≠0\tau\ne0, so any two samples of white noise, however close, are uncorrelated (and independent if Gaussian). The total power RW(0)=∫SW(f)dfR_W(0)=\int S_W(f)df is infinite, which is why white noise is only a model; after any filter with finite bandwidth the power becomes finite.

✓ Answer checked by Claude Opus 5.5 (high effort)

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