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UCS test soil type and parameters

Short answer

The unconfined compression test is for saturated cohesive soils (clays) that can stand without lateral support. A Mohr circle is drawn with σ3=0 and σ1=qu; for saturated clay φu=0, the horizontal envelope gives cu = qu/2.

On which type of soil is the unconfined shear test conducted? Explain with the help of Mohr circles how shear strength parameters are determined using the unconfined compressive strength test.

Soil type

The unconfined compression test is conducted on saturated, cohesive soils (clays) that can stand without lateral support, using undisturbed samples. It is not suitable for dry sands, gravels, or fissured clays, which cannot hold their shape without confining pressure.

Determination of strength parameters using Mohr circle

In the test, the lateral pressure is zero (σ3=0\sigma_3 = 0) and the axial stress is increased to failure:

σ1=qu=PAc,Ac=A01−ε\sigma_1 = q_u = \frac{P}{A_c}, \qquad A_c = \frac{A_0}{1-\varepsilon}

The Mohr circle at failure passes through the origin with diameter quq_u. For saturated clay, the undrained envelope is horizontal (ϕu=0\phi_u = 0), so the circle touches it at the top:

 tau
  |        ..--..
c_u ------*'     '*-------- envelope (phi_u = 0)
  |      /   C    \
  +-----+----+-----+----- sigma
  0 (s3=0)         q_u = s1
cu=qu2c_u = \frac{q_u}{2}

The failure plane would be at 45∘+ϕu/2=45∘45^\circ + \phi_u/2 = 45^\circ to the horizontal. If the sample is partly saturated and ϕu≠0\phi_u \neq 0, a single unconfined test cannot give both parameters; triaxial tests at different confining pressures are needed to find cuc_u and ϕu\phi_u. So the unconfined compression test is a quick test that gives only the undrained cohesion cu=qu/2c_u = q_u/2.

✓ Answer checked by Claude Opus 5.5 (high effort)

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