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Degree of curve, elements of simple curve

Short answer

Degree of curve D is the angle subtended at the centre by a 30 m arc; radius R = 1718.87/D. Elements of simple circular curve: T = R tan(Δ/2), L = πRΔ/180, LC = 2R sin(Δ/2), E = R(sec(Δ/2)-1), M = R(1-cos(Δ/2)). PC chainage = IP - T, PT chainage = PC + L.

What is degree of curve? Describe the elements of simple circular curve.

Degree of curve

The degree of curve DD is the angle subtended at the centre by a standard arc (or chord) of fixed length CC, usually 30 m in metric practice (100 ft in foot units). It expresses the sharpness of the curve: a bigger DD means a smaller radius.

D=180∘ CπR⇒R=1718.87D  (C=30 m)D = \frac{180^\circ\,C}{\pi R}\quad\Rightarrow\quad R = \frac{1718.87}{D}\ \ (C = 30\ \text{m})

Elements of a simple circular curve

              V (IP)
             /\
          T /  \ T
           / Δ  \
      T1  /      \  T2
       o'--------'o
         \ M  E /
          \ __ /
          R \  / R
             O
  • T₁ (PC) and T₂ (PT): the points where the curve begins and ends.
  • Deflection angle Δ\Delta: angle between the forward extension of the back tangent and the forward tangent; it equals the angle subtended at the centre by the curve.
  • Tangent length: T=Rtan⁡(Δ/2)T = R\tan(\Delta/2).
  • Length of curve: L=πRΔ/180L = \pi R\Delta/180.
  • Long chord: LC=2Rsin⁡(Δ/2)LC = 2R\sin(\Delta/2).
  • External (apex) distance: E=R(sec⁡(Δ/2)−1)E = R(\sec(\Delta/2) - 1), from IP to the mid-point of the curve.
  • Mid-ordinate (versed sine): M=R(1−cos⁡(Δ/2))M = R(1 - \cos(\Delta/2)), from the mid-point of the long chord to the mid-point of the curve.
  • Chainages: T₁ = IP − TT; T₂ = T₁ + LL.

Example: Δ=40∘\Delta = 40^\circ, D=4∘D = 4^\circ gives R=429.72R = 429.72 m, T=156.40T = 156.40 m and L=300.00L = 300.00 m.

✓ Answer checked by Claude Opus 5.5 (high effort)

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