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Simple curve by offsets from long chord

Short answer

The curve is set out by measuring perpendicular offsets from the long chord joining T₁ and T₂. Offset at distance x from the midpoint is O_x = √(R² − x²) − (R − O0), where O0 = R(1 − cos(Δ/2)) is the mid-ordinate. The method requires only tape and cross-staff, and is suitable for short, accessible curves.

Explain the setting out of simple circular curve by offsets from long chord.

Offsets from the long chord is a chain-and-tape method (no theodolite needed) in which the curve is located by perpendicular offsets measured from the long chord joining the two tangent points T₁ and T₂. It is used for short curves.

        T1 ______________ T2   <- long chord
          \  |  |  |  |  /
           \ |  |  |  | /     offsets O_x
            '-.__.__.-'

Principle

Let OO be the centre, RR the radius, Δ\Delta the deflection angle.

  • Long chord: LC=2Rsin⁡Δ2LC = 2R\sin\dfrac{\Delta}{2}
  • Mid-ordinate (at the middle of the long chord): O0=R(1−cos⁡Δ2)O_0 = R\left(1-\cos\dfrac{\Delta}{2}\right)
  • Offset at a distance xx from the middle of the long chord:
Ox=R2−x2−(R−O0)O_x = \sqrt{R^2 - x^2} - (R - O_0)

The term R−O0=Rcos⁡(Δ/2)R - O_0 = R\cos(\Delta/2) is the distance from the centre to the long chord, so OxO_x is the height of the curve above the chord at that point.

Procedure

  1. Locate T₁ and T₂ by measuring the tangent length T=Rtan⁡(Δ/2)T = R\tan(\Delta/2) from the IP; join them to get the long chord.
  2. Measure the long chord, mark its mid point M.
  3. Divide the long chord on both sides of M at equal intervals (say 5 or 10 m): x=0,5,10,…x = 0, 5, 10, \dots.
  4. Compute OxO_x for each xx; the offsets are symmetrical on both sides of M.
  5. Set out each offset perpendicular to the long chord (using a cross-staff or optical square) and fix the curve pegs.
  6. The offsets at T₁ and T₂ are zero; the offset at M is the mid-ordinate O0O_0 (check).

Use: short curves where the chord is accessible and level; accuracy is limited by the perpendicular setting.

✓ Answer checked by Claude Opus 5.5 (high effort)

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