- 2073 Bhadra · 4 marks
Simple curve by offsets from long chord
Short answer
The curve is set out by measuring perpendicular offsets from the long chord joining T₁ and T₂. Offset at distance x from the midpoint is O_x = √(R² − x²) − (R − O0), where O0 = R(1 − cos(Δ/2)) is the mid-ordinate. The method requires only tape and cross-staff, and is suitable for short, accessible curves.
Explain the setting out of simple circular curve by offsets from long chord.
Offsets from the long chord is a chain-and-tape method (no theodolite needed) in which the curve is located by perpendicular offsets measured from the long chord joining the two tangent points T₁ and T₂. It is used for short curves.
T1 ______________ T2 <- long chord
\ | | | | /
\ | | | | / offsets O_x
'-.__.__.-'
Principle
Let be the centre, the radius, the deflection angle.
- Long chord:
- Mid-ordinate (at the middle of the long chord):
- Offset at a distance from the middle of the long chord:
The term is the distance from the centre to the long chord, so is the height of the curve above the chord at that point.
Procedure
- Locate T₁ and T₂ by measuring the tangent length from the IP; join them to get the long chord.
- Measure the long chord, mark its mid point M.
- Divide the long chord on both sides of M at equal intervals (say 5 or 10 m): .
- Compute for each ; the offsets are symmetrical on both sides of M.
- Set out each offset perpendicular to the long chord (using a cross-staff or optical square) and fix the curve pegs.
- The offsets at T₁ and T₂ are zero; the offset at M is the mid-ordinate (check).
Use: short curves where the chord is accessible and level; accuracy is limited by the perpendicular setting.
✓ Answer checked by Claude Opus 5.5 (high effort)
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