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Setting out right hand side composite curve

Short answer

Set out with theodolite and tape by deflection angles. TS and ST are located by measuring Ts from IP on both tangents. First transition from TS uses clockwise tangential angles; circular arc from SC uses clockwise deflection angles; second transition from ST uses anticlockwise angles. Check joins at SC and CS.

Describe about the setting out techniques of right hand side composite curve.

A composite curve has a circular arc between two transition (spiral) curves. A right-hand curve turns to the right of the direction of travel, so the deflection angles are measured clockwise. It is set out with a theodolite and tape by the deflection angle method.

            V (IP)
           /  \
          /    \
    TS o/        \o ST
        \ SC  CS /
         '--___--'

Preliminary computations

  1. Length of spiral Ls=v3/(CR)L_s = v^3/(CR), shift s=Ls2/(24R)s = L_s^2/(24R), spiral angle θs=Ls/(2R)\theta_s = L_s/(2R).
  2. Tangent length Ts=(R+s)tan⁡(Δ/2)+Ls/2T_s = (R+s)\tan(\Delta/2) + L_s/2; Lc=R(Δ−2θs)L_c = R(\Delta - 2\theta_s).
  3. Chainages: TS = IP − TsT_s, SC = TS + LsL_s, CS = SC + LcL_c, ST = CS + LsL_s.
  4. Deflection angles of the transition: α=573 l2/(RLs)\alpha = 573\,l^2/(RL_s) minutes; of the circular arc: δ=1718.87 c/R\delta = 1718.87\,c/R minutes.

Field procedure

  1. Locate TS and ST by measuring TsT_s from the IP along both tangents.
  2. First transition (instrument at TS): set zero and sight the IP. Turn the telescope clockwise by α1\alpha_1, measure l1l_1 (sub-chord) from TS to fix point 1. Then set α2\alpha_2, swing the tape from point 1 and fix point 2, and so on to SC. The last angle is αs=θs/3\alpha_s = \theta_s/3.
  3. Circular arc (instrument at SC): sight TS with the plates set at 360∘−23θs360^\circ - \tfrac{2}{3}\theta_s, plunge the telescope and turn clockwise until the circle reads 0∘00′00′′0^\circ00'00''; this line is the tangent at SC. Set clockwise deflection angles δ1, δ1+δ2,…\delta_1,\ \delta_1+\delta_2,\dots and fix the arc points with the chords. The last angle should be (Δ−2θs)/2(\Delta-2\theta_s)/2 at CS.
  4. Second transition (instrument at ST): set zero and sight the IP. Because this transition is set from the far end, the points are located by angles measured anticlockwise (reading 360∘−α360^\circ - \alpha for a right-hand curve), with ll measured from ST back to CS.
  5. Check: the arc and the two transitions must join exactly at SC and CS; any small misclosure is distributed over the last few pegs.

If the full curve is not visible from the SC (obstruction), the instrument is shifted to an intermediate station and re-oriented by backsighting.

✓ Answer checked by Claude Opus 5.5 (high effort)

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