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Optical distance principle, tangential horizontal distance

Short answer

Optical distance measurement derives distance from a known base and a measured small angle: D=s/2 cot(β/2). In the tangential method, vertical angles to two targets s apart are measured; D=s/(tanθ1-tanθ2), V=D tanθ2, RL=axis+V-h. For both depression angles, D=s/(tanα1-tanα2) and RL=axis-H tanα1-h.

Explain the principle of optical distance measurement. Discuss measurement of horizontal distance by tangential method.

Principle: in optical distance measurement the distance to a point is found with the instrument alone, from a small angle subtended at the instrument by a known length (or from the length subtended by a known angle), instead of taping the distance. It rests on the geometry of a thin isosceles triangle:

D=s2cot⁡β2≈sβD=\frac{s}{2}\cot\frac{\beta}{2}\approx\frac{s}{\beta}

where ss is the base (known length) and β\beta the parallactic angle at the instrument.

 Instrument                       Staff / bar
     O  <-------------- D -------------->  A
      \  beta                              | s
       \_________________________________  B

Depending on which quantity is fixed:

  1. Stadia method: the angle β\beta is fixed by two stadia hairs in the telescope, and the intercept ss on the staff varies. D=Ks+CD=Ks+C.
  2. Subtense method: the length ss is fixed (a subtense bar, 2 m long) and the angle β\beta is measured with the theodolite. D=s2cot⁡β2D=\frac{s}{2}\cot\frac{\beta}{2}.
  3. Tangential method: the vertical angles to two targets a known distance apart on a staff are measured. D=s/(tan⁡θ1−tan⁡θ2)D=s/(\tan\theta_1-\tan\theta_2).

The horizontal distance and the difference in elevation are then found from the distance and the vertical angle, so detail surveys and contouring can be done faster than by chaining, especially in rough ground.

Horizontal distance by the tangential method

In the tangential method the stadia hairs are not used. The telescope is pointed at two targets (vanes) on a staff, a known distance ss apart, and the two vertical angles are measured. The distance is calculated from the tangents of these angles. It is used when the telescope has no stadia hairs, or when the staff is too far away for the stadia hairs to be read accurately.

                   _ B  (upper target)
               _ -  |
        theta1 -    | s
    O  ----------   A  (lower target)  
        theta2 \_   |
 axis ----------\__ |       horizontal
                  D

Let DD be the horizontal distance of the staff from the instrument axis, and VV the vertical height of the lower target above (or below) the axis.

Horizontal distance and vertical distance

When both angles are angles of elevation, θ1\theta_1 (upper target) and θ2\theta_2 (lower target), with the vanes ss apart:

D=stan⁡θ1−tan⁡θ2,V=Dtan⁡θ2D=\frac{s}{\tan\theta_1-\tan\theta_2},\qquad V=D\tan\theta_2 RL of staff station=RL of axis+V−h\text{RL of staff station}=\text{RL of axis}+V-h

where hh is the height of the lower vane above the ground at the staff station. When both are angles of depression, α1\alpha_1 (lower target) and α2\alpha_2 (upper target), with α1>α2\alpha_1>\alpha_2:

D=stan⁡α1−tan⁡α2,RL=RL of axis−Dtan⁡α2−s−hD=\frac{s}{\tan\alpha_1-\tan\alpha_2},\qquad \text{RL}=\text{RL of axis}-D\tan\alpha_2-s-h

The method needs only the vertical circle of the theodolite and can be used at long distances, but the angles must be measured carefully, because an angle error dθd\theta is magnified in DD by the small difference (tan⁡θ1−tan⁡θ2)(\tan\theta_1-\tan\theta_2) in the denominator.

✓ Answer checked by Claude Opus 5.5 (high effort)

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