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Tangential method distance and elevation

Short answer

Measure vertical angles θ1 and θ2 to two targets a known distance s apart on a staff, without using stadia hairs. Horizontal distance D = s/(tanθ1 − tanθ2) and vertical component V = D tanθ2. The staff station RL equals RL of axis + V − h, where h is the lower target height above ground.

Discuss measurement of horizontal and vertical distance by tangential method.

In the tangential method the stadia hairs are not used. The telescope is pointed at two targets (vanes) on a staff, a known distance ss apart, and the two vertical angles are measured. The distance is calculated from the tangents of these angles. It is used when the telescope has no stadia hairs, or when the distance is too large for the stadia intercept to be read accurately.

                   _ B  (upper target)
               _ -  |
        theta1 -    | s
    O  ----------   A  (lower target)  
        theta2 \_   |
 axis ----------\__ |       horizontal
                  D

Let DD be the horizontal distance of the staff from the instrument axis, and VV the vertical height of the lower target above (or below) the axis.

Horizontal distance and vertical distance

For two angles of elevation, θ1\theta_1 (upper target) and θ2\theta_2 (lower target), with the vanes ss apart:

D=stan⁡θ1−tan⁡θ2,V=Dtan⁡θ2D=\frac{s}{\tan\theta_1-\tan\theta_2},\qquad V=D\tan\theta_2 RL of staff station=RL of axis+V−h\text{RL of staff station}=\text{RL of axis}+V-h

where hh is the height of the lower vane above the ground at the staff station. For two angles of depression, α1\alpha_1 (lower target) >α2>\alpha_2 (upper target):

D=stan⁡α1−tan⁡α2,RL=RL of axis−Dtan⁡α2−s−hD=\frac{s}{\tan\alpha_1-\tan\alpha_2},\qquad \text{RL}=\text{RL of axis}-D\tan\alpha_2-s-h

For one angle of elevation θ\theta (upper target) and one of depression α\alpha (lower target): D=s/(tan⁡θ+tan⁡α)D=s/(\tan\theta+\tan\alpha) and RL == RL of axis −Dtan⁡α−h-D\tan\alpha-h.

The method needs only the vertical circle of the theodolite and works even at long distances, but the angles must be measured carefully, because tan⁡θ1−tan⁡θ2\tan\theta_1-\tan\theta_2 is small and a small error in either angle causes a large error in DD.

✓ Answer checked by Claude Opus 5.5 (high effort)

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