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Frame buffer size for 1 min video

Short answer

Frame size = 1280×1024×24 bits = 3.75 MB. For 1 minute at 25 fps, total frames = 1500, resulting in 5.9×10^9 bytes ≈ 5.49 GB of uncompressed video storage.

Calculate the frame buffer size for a raster system recording a video for 1 min with a resolution of 1280 × 1024, storing 24 bits per pixel and with a refresh rate of 25 fps.

A frame buffer must hold the colour of every pixel of the frame. For a video, the total storage is the size of one frame multiplied by the number of frames.

Given: resolution 1280 × 1024, 24 bits/pixel, 25 fps, time = 1 min = 60 s.

Pixels per frame   = 1280 × 1024            = 1,310,720
Bits per frame     = 1,310,720 × 24         = 31,457,280 bits
Bytes per frame    = 31,457,280 / 8         = 3,932,160 B = 3.75 MB
Frames in 1 minute = 25 × 60                = 1500
Total size         = 3,932,160 × 1500       = 5,898,240,000 bytes
                                            ≈ 5.49 GB (÷ 2³⁰)

The frame buffer for a single refreshed frame is 3.75 MB. The storage needed to hold the whole 1 minute video without compression is 5,898,240,000 bytes.

Answer: one frame = 3.75 MB; 1 minute of video = 5.9 × 10⁹ bytes ≈ 5.49 GB.

✓ Answer checked by Claude Opus 5.5 (high effort)

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