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Memory for 10 minute SVGA video

Short answer

Assuming SVGA 800×600, one frame = 800×600×24 bits = 1.37 MB. For 10 minutes at 60 fps, total frames = 36,000, requiring approximately 5.18×10^10 bytes (48.3 GB) of storage.

Calculate the total memory (frame buffer size) required to store a 10 minute video in a SVGA system with 24 bit true color (without compression), with a 60 fps refresh rate.

Assume SVGA resolution = 800 × 600 pixels.

Bits per pixel      = 24 (true colour)
Bits per frame      = 800 × 600 × 24   = 11,520,000 bits
Bytes per frame     = 11,520,000 / 8   = 1,440,000 B ≈ 1.37 MB
Time                = 10 min × 60      = 600 s
Frames              = 60 fps × 600 s   = 36,000
Total memory        = 1,440,000 × 36,000
                    = 51,840,000,000 bytes
                    ≈ 48.28 GB (÷ 2³⁰)   (≈ 51.84 GB in decimal)

Answer: about 5.18 × 10¹⁰ bytes ≈ 48.3 GB (one frame buffer = 1.37 MB).

✓ Answer checked by Claude Opus 5.5 (high effort)

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