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ACI mix design for fck 30 MPa (numerical)

Short answer

ACI method with given w/c 0.48: water 205 kg/m³, cement 427 kg/m³, coarse aggregate 992 kg/m³, fine aggregate 721 kg/m³. Mix ratio1:1.69:2.32.

Design the mix proportion for concrete with the help of the following particulars using the American Concrete Institute (ACI) method: characteristic compressive strength, fckf_{ck} = 30 MPa; water cement ratio based on the compressive strength = 0.48. Assume all necessary data.

Method: ACI 211.1, with the w/c given as 0.48.

Assumed data: maximum size 20 mm (19 mm in the ACI tables); slump 75-100 mm; non-air-entrained, entrapped air 2%; GFA=2.65G_{FA} = 2.65, GCA=2.70G_{CA} = 2.70, cement 3.15; dry-rodded density of CA = 1600 kg/m3^3; FM of sand = 2.8.

Step 1: Water (ACI Table 6.3.3, 75-100 mm, 19 mm) = 205 kg/m3^3, air = 2%.

Step 2: w/c = 0.48 (given). From the ACI w/c table (0.47 at 35 MPa, 0.54 at 30 MPa), this corresponds to an average strength of about 34 MPa, a margin of about 4 MPa over fckf_{ck} = 30 MPa.

Step 3: Cement = 205/0.48=427205/0.48 = 427 kg/m3^3.

Step 4: Coarse aggregate = 0.62×1600=9920.62 \times 1600 = 992 kg/m3^3 (Table 6.3.6, 19 mm, FM 2.8).

Step 5: Fine aggregate by absolute volume

IngredientMass (kg)Volume (m3^3)
Water2050.2050
Cement4270.1356
CA9920.3674
Air-0.0200
Sum0.7280

VFA=1−0.7280=0.2720V_{FA} = 1 - 0.7280 = 0.2720 m3^3, FA=0.2720×2650=721FA = 0.2720 \times 2650 = 721 kg/m3^3.

Answer (per m3^3): cement 427 kg, water 205 kg, FA 721 kg, CA 992 kg; ratio 1 : 1.69 : 2.32 with w/c = 0.48 (total about 2345 kg/m3^3). Correct for the moisture and absorption of the aggregates at site, then confirm by trial batches.

✓ Answer checked by Claude Opus 5.5 (high effort)

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