- 2068 Baisakh (old course) · 5 marks
Characteristic strength at 95% confidence
Short answer
Mean of 10 results = 21.60 N/mm², sample standard deviation s = 4.766 N/mm². Characteristic strength f_ck = f_m – 1.65s = 21.60 – 1.65×4.766 = 13.74 N/mm² (≈13.7 N/mm²), assuming normal distribution.
The compressive strength test results of a concrete specimen were found as 16; 17; 19; 21; 22; 25; 26; 27; 28 and 15 N/mm. Calculate the characteristic strength of the test result at 95% confidence level.
Characteristic strength is the value of strength below which not more than 5% of the test results are expected to fall (IS 456, Terminology).
Formula: characteristic strength (95% confidence) , with the sample standard deviation . The factor 1.65 comes from the normal distribution (the same factor is used in mix design, , IS 10262). Assumptions: the results follow the normal distribution, and the sample standard deviation () is used.
, , mean N/mm.
| No. | |||
|---|---|---|---|
| 1 | 16 | -5.60 | 31.36 |
| 2 | 17 | -4.60 | 21.16 |
| 3 | 19 | -2.60 | 6.76 |
| 4 | 21 | -0.60 | 0.36 |
| 5 | 22 | +0.40 | 0.16 |
| 6 | 25 | +3.40 | 11.56 |
| 7 | 26 | +4.40 | 19.36 |
| 8 | 27 | +5.40 | 29.16 |
| 9 | 28 | +6.40 | 40.96 |
| 10 | 15 | -6.60 | 43.56 |
| Sum | 204.40 |
Answer: characteristic strength 13.7 N/mm.
✓ Answer checked by Claude Sonnet 5.5
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