Skip to main content

Elastic properties and modulus of elasticity

Short answer

Concrete is not perfectly elastic; at working stress it is linear with modulus Ec=5000√fck (e.g.,22360 N/mm² for M20). Poisson's ratio is0.15–0.20. Modulus increases with higher strength, stiffer aggregates, age, and moisture.

Describe the elastic properties and the modulus of elasticity (Young's modulus) of concrete.

Elastic properties

Concrete is a composite of paste, aggregate and interface, and so it is not truly elastic. On loading, the stress-strain curve is nearly straight up to about 30 to 40% of the ultimate stress, then curves as microcracks grow. For design, concrete is treated as elastic at working stress. The elastic properties are the modulus of elasticity EE, Poisson's ratio μ\mu (0.15 to 0.20 for concrete) and modulus of rigidity G=E/[2(1+μ)]G = E/[2(1+\mu)].

Modulus of elasticity (Young's modulus)

It is the ratio of stress to strain within the elastic range:

E=σεE = \frac{\sigma}{\varepsilon}
  • Initial tangent, tangent, secant and chord moduli are used (secant at about 33% of fcf_c is the static modulus).
  • Dynamic modulus from UPV or resonant frequency is higher than static modulus.
  • IS 456 (Cl. 6.2.3.1): Ec=5000fckE_c = 5000\sqrt{f_{ck}} N/mm2^2. For M20: Ec=5000×4.472=22360E_c = 5000\times4.472 = 22360 N/mm2^2.

Factors affecting EE

  • Higher strength (lower W/C) gives a higher EE.
  • Stiffer aggregates (granite) and a higher aggregate content give a higher EE; light-weight aggregate gives a lower EE.
  • Moist concrete has a higher EE than dry concrete; porosity reduces EE.
  • EE increases with age. A slower rate of loading gives a lower apparent value because of creep.

EE is used to calculate deflection, to find the modular ratio m=280/(3σcbc)m = 280/(3\sigma_{cbc}) (IS 456, Annex B) and to find the stress distribution in composite sections.

✓ Answer checked by Claude Sonnet 5.5

All Concrete Technology and Masonry Structure chapter 4 questions →