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Safe load on a brick masonry column

Short answer

SR based on least lateral dimension: 3500/340=10.29, k_s=0.883, area <0.2 m² gives k_a=0.935, f_c=0.907 N/mm², safe axial load=142 kN. For 460×460 column: SR=7.61, k_s=0.96, k_a=1.0, f_c=1.056 N/mm², load=223 kN.

A brick masonry column of cross-section 340 mm × 460 mm and height 3.5 m is laterally restrained at the top and bottom but not rotationally (effective height = actual height). The basic compressive stress is fb=1.1f_b = 1.1 N/mm². Using IS 1905 with ksk_s from SR 10 → 0.89, SR 12 → 0.84, find the safe axial load. Compare it with that of a 460 mm × 460 mm column.

Slenderness (column)

Slenderness is based on the least lateral dimension:

Heff=3500 mm,SR=3500340=10.29H_{eff} = 3500\ \text{mm}, \qquad SR = \frac{3500}{340} = 10.29 ks=0.89−0.292×0.05=0.883k_s = 0.89 - \frac{0.29}{2}\times 0.05 = 0.883

Area factor

A=0.34×0.46=0.1564A = 0.34 \times 0.46 = 0.1564 m² <0.2< 0.2 m²

ka=0.7+1.5×0.1564=0.935k_a = 0.7 + 1.5\times0.1564 = 0.935

kp=1.0k_p = 1.0 for brick.

Permissible stress and safe load

fc=fb ks ka kp=1.1×0.883×0.935×1.0=0.907 N/mm2P=fcA=0.907×340×460=141 900 N≈142 kN\begin{aligned} f_c &= f_b\,k_s\,k_a\,k_p = 1.1 \times 0.883 \times 0.935 \times 1.0 = 0.907\ \text{N/mm}^2 \\ P &= f_c A = 0.907 \times 340 \times 460 = 141\,900\ \text{N} \approx 142\ \text{kN} \end{aligned}

Comparison with 460 × 460 mm column

For SR<10SR < 10 the full IS 1905 table is needed (SR 6 → 1.00, SR 8 → 0.95). SR=3500/460=7.61SR = 3500/460 = 7.61, so ks=0.95+(8−7.61)/2×0.05=0.96k_s = 0.95 + (8 - 7.61)/2 \times 0.05 = 0.96; A=0.2116A = 0.2116 m² >0.2> 0.2, so ka=1.0k_a = 1.0.

fc=1.1×0.96×1.0=1.056 N/mm2,P=1.056×460×460=223 400 N=223 kNf_c = 1.1 \times 0.96 \times 1.0 = 1.056\ \text{N/mm}^2, \qquad P = 1.056 \times 460 \times 460 = 223\,400\ \text{N} = 223\ \text{kN}
ColumnSRSRksk_skak_afcf_c (N/mm²)Safe load (kN)
340 × 46010.290.8830.9350.907142
460 × 4607.610.9601.0001.056223

The larger column carries 57 percent more load because of its larger area and lower slenderness. The self-weight of the column (19×0.1564×3.5=10.419 \times 0.1564 \times 3.5 = 10.4 kN) should be deducted from the safe load to get the superimposed load, about 131 kN for the 340 × 460 column.

Answer: Safe axial load ≈ 142 kN for 340 × 460 mm (about 131 kN superimposed after self-weight) and ≈ 223 kN for 460 × 460 mm.

✓ Answer checked by Claude Sonnet 5.5

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