Skip to main content

Column 35x40 cm, not restrained against rotation

Short answer

Column is short since slenderness ratios are 7.75 and 8.86. Biaxial interaction check is safe with 20-16 mm longitudinal bars (Asc 4021 mm2, 2.87%) and 8 mm ties at 250 mm c/c.

A RC column of size 35 cm x 40 cm with unsupported length of 3.10 m is subjected to a factored axial load of 1500 kN and biaxial moments, MuxM_{ux} = 125 kNm and MuyM_{uy} = 88 kNm. The ends of the column are effectively held in position but not restrained against rotation. Design the column for longitudinal and transverse reinforcements and sketch the details. Use M25 Concrete and Fe500 grade steel.

Data and assumptions

  • Column 350 mm (width bb) × 400 mm (depth DD); Pu=1500P_u = 1500 kN; fck=25f_{ck} = 25 MPa, fy=500f_y = 500 MPa. Clear cover 40 mm (IS 456 cl. 26.4.2.1), 8 mm ties.
  • Moments: about major axis (x-x) MuxM_{ux} = 125 kN·m; about minor axis (y-y) MuyM_{uy} = 88 kN·m.
  • Held in position but not restrained against rotation at both ends: le=L=3.1l_e = L = 3.1 m (IS 456 Table 28).
  • Sizes are given as b×Db \times D with D≥bD \ge b; moments MuxM_{ux} act about the major axis (depth DD) and MuyM_{uy} about the minor axis (depth bb).

Slenderness

Axislel_e (mm)Dimension (mm)le/l_e/dimType
x-x (about major)31004007.75short
y-y (about minor)31003508.86short

Both ratios are below 12, so the column is short; no additional moment is required.

Minimum eccentricity (cl. 25.4)

emin=max⁡(L500+D30, 20)e_{min} = \max\left(\frac{L}{500} + \frac{D}{30},\ 20\right)
  • About x-x: ex=3100/500+400/30=19.5e_x = 3100/500 + 400/30 = 19.5 mm (min. 20 mm); adopt 20.0 mm; Mux,min=Pue=30.0M_{ux,min} = P_u e = 30.0 kN·m
  • About y-y: ey=3100/500+350/30=17.9e_y = 3100/500 + 350/30 = 17.9 mm (min. 20 mm); adopt 20.0 mm; Muy,min=30.0M_{uy,min} = 30.0 kN·m

Design moments

  • Design moments: Mux=125.0M_{ux} = 125.0 kN·m, Muy=88.0M_{uy} = 88.0 kN·m (not less than the minimum-eccentricity values).

Longitudinal reinforcement

PufckbD=150000025×350×400=0.429\dfrac{P_u}{f_{ck} b D} = \dfrac{1500000}{25 \times 350 \times 400} = 0.429 Bars are chosen so that pp lies between 0.8% (minimum) and 4% (practical maximum; IS 456 cl. 26.5.3.1 allows 6%). The uniaxial capacities Mux1M_{ux1}, Muy1M_{uy1} at PuP_u are read from the SP-16 interaction charts for rectangular sections; here they are computed by strain compatibility with the IS 456 stress block and the design stress-strain curve of steel (same basis as the charts), with effective cover d′=40+8+ϕ/2d' = 40 + 8 + \phi/2.

Trialpp (%)d′/Dd'/DMux1M_{ux1}Muy1M_{uy1}Pu/PuzP_u/P_{uz}αn\alpha_n(Mux/Mux1)αn+(Muy/Muy1)αn(M_{ux}/M_{ux1})^{\alpha_n}+(M_{uy}/M_{uy1})^{\alpha_n}
12-20 φ2.690.145175.7145.80.5091.521.063 ✗
8-25 φ2.800.151182.7151.10.4991.501.011 ✗
20-16 φ2.870.140184.7153.60.4941.490.995 ✓

Check

Puz=0.45fckAc+0.75fyAsc=0.45×25×135979+0.75×500×4021=3038P_{uz} = 0.45 f_{ck} A_c + 0.75 f_y A_{sc} = 0.45 \times 25 \times 135979 + 0.75 \times 500 \times 4021 = 3038 kN PuPuz=15003038=0.494\dfrac{P_u}{P_{uz}} = \dfrac{1500}{3038} = 0.494, so αn=1.49\alpha_n = 1.49 (IS 456 cl. 39.6; linear between 1.0 at 0.2 and 2.0 at 0.8).

(MuxMux1)αn+(MuyMuy1)αn=(125.0184.7)1.49+(88.0153.6)1.49=0.995≤1.0\left(\frac{M_{ux}}{M_{ux1}}\right)^{\alpha_n} + \left(\frac{M_{uy}}{M_{uy1}}\right)^{\alpha_n} = \left(\frac{125.0}{184.7}\right)^{1.49} + \left(\frac{88.0}{153.6}\right)^{1.49} = 0.995 \le 1.0

The interaction condition is satisfied; the section is safe.

Provide 20-16 mm bars (Asc=4021A_{sc} = 4021 mm², p=2.87%p = 2.87\%), within 0.8% to 4%.

Lateral ties

  • Diameter ≥max⁡(ϕmax/4, 6)=max⁡(16/4,6)=6\ge \max(\phi_{max}/4,\ 6) = \max(16/4, 6) = 6 mm → provide 8 mm.
  • Pitch ≤min⁡\le \min(least lateral dimension, 16ϕmin16\phi_{min}, 300 mm) =min⁡(350,256,300)=256= \min(350, 256, 300) = 256 mm → provide 8 mm ties @ 250 mm c/c.

Detailing

CROSS-SECTION 350 x 400
    +-------------------------+
    |                         |
    |   o   o  o   o  o   o   |
    |   o                 o   |
    |                         |
    |   o                 o   |
    |                         |
    |   o                 o   |
    |                         |
    |   o                 o   |
    |   o   o  o   o  o   o   |
    |                         |
    +-------------------------+
   o = 16 mm bars, ties 8 mm @ 250 c/c

Answer: 350 × 400 mm column with 20-16 mm longitudinal bars (p=2.87%p = 2.87\%) and 8 mm ties @ 250 mm c/c.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Design of RCC Structure chapter 10 questions →