- 2071 Shrawan · 8 marks
Free water evaporation by Penman method, June
Short answer
Free water surface evaporation = 9.2 mm/day (about 275 mm in June).
Calculate the free water surface evaporation in June using the Penman method from an area whose latitude is approximately 33N. The available data include air temperature = 30C, wind speed at 2 m height = 10 km/h, relative humidity = 60%, mean observed sun shine hours = 12 and reflection coefficient = 0.05.
Free-water evaporation is obtained from Penman with for a water surface.
Penman equation (potential evapotranspiration):
with
where is the net radiation in mm of evaporable water per day, the aerodynamic term in mm/day, the wind speed at 2 m in km/day, and in mm of Hg.
Data and constants used
- C K; RH ; h; h; km/day
- mm/day; ; ; mm Hg; mm Hg/C; mm Hg/C; mm/day/K
- Assumed values (not given): at C mm Hg and slope mm Hg/C; for N in June, mm/day and possible sunshine h (standard tables / solar geometry); wind km/day; .
Step 1: Actual vapour pressure
Step 2: Net radiation
, and
Step 3: Aerodynamic term
Step 4: PET
Answer: Free water surface evaporation = 9.2 mm/day, so about 275 mm in June (30 days).
✓ Answer checked by Claude Sonnet 5.5
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