Skip to main content

Effect of increasing hump height on water surface

Short answer

For a hump less than critical height, upstream depth is unchanged and depth over the hump falls along the subcritical limb. At critical hump height, upstream depth is still unchanged but the hump acts as a control with critical flow. If the hump exceeds critical height, the flow backs up, upstream depth increases, and critical depth occurs over the hump.

Explain briefly, by sketching the graph between specific energy and water depth of a rectangular channel, how the depth upstream of a hump changes with the height of hump as it is gradually increased in three stages: (i) less than the critical hump height; (ii) at the critical hump height, and (iii) exceeding the critical hump height. (The same analysis may be asked for a hump together with a constriction of constant width.)

Set-up

Consider a rectangular channel with discharge qq per unit width, approach depth y1y_1 (subcritical) and specific energy E1=y1+q22gy12E_1=y_1+\dfrac{q^2}{2gy_1^2}. A hump of height Δz\Delta z is placed on the bed. With no energy loss, the specific energy over the hump is

E2=E1−ΔzE_2=E_1-\Delta z

On the specific energy diagram, moving onto the hump shifts the state to the left by Δz\Delta z. The critical hump height is Δzc=E1−Emin=E1−32yc\Delta z_c=E_1-E_{min}=E_1-\tfrac32y_c.

  y ^
    |                       .
 y1 |----------------------*   (1) upstream, E1
    |                  .
 y2 |-------------*            (2) over hump, case (i): E2 = E1 - dz
    |        .
 yc |-----*                    critical point, E_min (case ii: E2 = E_min)
    |        .
    |             .
    |                   .      supercritical limb
    +-----+-------+--------+-----> E
        E_min     E2       E1
                  |<- dz ->|

(i) Hump height less than critical (Δz<Δzc\Delta z<\Delta z_c)

  • E2=E1−Δz>EminE_2=E_1-\Delta z>E_{min}, so flow over the hump is possible with the same discharge.
  • The upstream depth y1y_1 is unchanged.
  • The depth over the hump falls along the subcritical limb (it is lower than y1y_1 but still greater than ycy_c). The water surface drops over the hump.
  • After the hump the depth rises again to y1y_1.

(ii) Hump height equal to critical (Δz=Δzc\Delta z=\Delta z_c)

  • E2=EminE_2=E_{min}, so the depth over the hump is exactly critical (y=ycy=y_c).
  • The upstream depth is still y1y_1 (unchanged), but this is the limit: the hump now acts as a control (like a broad-crested weir).
  • The discharge is the maximum that can pass for this upstream energy.

(iii) Hump height greater than critical (Δz>Δzc\Delta z>\Delta z_c)

  • E1−Δz<EminE_1-\Delta z<E_{min}: the energy available over the hump is less than the minimum required for qq, so the flow cannot pass with the given upstream energy.
  • The flow backs up: the upstream depth rises to y1′y_1' so that the upstream energy becomes E1′=Emin+ΔzE_1'=E_{min}+\Delta z.
  • Critical depth occurs over the hump, and downstream of the hump the flow becomes supercritical (and may end in a hydraulic jump).
  • Increasing the hump height further raises the upstream depth further.
StageOver humpUpstream depth
Δz<Δzc\Delta z<\Delta z_csubcritical, y>ycy>y_cunchanged
Δz=Δzc\Delta z=\Delta z_ccriticalunchanged (limit)
Δz>Δzc\Delta z>\Delta z_ccriticalincreases (backwater)

If the hump is combined with a constriction of constant width, the same logic applies, with qq increased in the contracted section: the critical condition is E1−Δz=32ycE_1-\Delta z=\tfrac32y_c, with yc=q22/g3y_c=\sqrt[3]{q_2^2/g} and q2=Q/b2q_2=Q/b_2.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Hydraulics chapter 7 questions →