- 2081 Chaitra · 8 marks
Water surface over hump with contraction
Short answer
Upstream water surface elevation remains 1.600 m. Over the 0.35 m hump and 3.5 m width, the depth is 1.158 m, giving a surface elevation of 1.508 m above the upstream bed.
Water flows at a depth of 1.6 m and velocity of 1.10 m/s in an open channel of rectangular cross section of width 4.0 m. At a certain section the width is reduced to 3.5 m and the bed is raised by 0.35 m through a smooth flat top hump. Calculate the water surface elevations at the contracted section as well as at a section upstream of it. Assume energy losses to be negligible. Show the results in specific energy diagram.
Given data
m, m/s, m; contracted width m with a hump of m; no losses.
Check for critical flow at the contraction
Energy available over the hump: m . So the flow passes without choking, and the upstream depth is unchanged.
Depth over the hump (subcritical)
(here ). Velocity m/s.
Water surface elevations (datum: upstream bed)
- At a section upstream: m.
- At the contracted section: m.
Drop in water surface m.
Specific energy diagram
y (m)
1.700| .:
1.600| 1: (1) upstream, E1 = 1.662 m
1.500| .:
1.400| .:
1.300| .:
1.158| .2 (2) over hump, E2 = 1.312 m
1.100| . :
1.000| . :
0.900| . :
0.800| . :
0.700| . : noses: yc1 = 0.681 m, yc2 = 0.744 m
0.600| . :
0.500| . :
0.400| . :
+-----+---+------+-------------+---------> E (m)
ticks, left to right: E_min1 = 1.021, E_min2 = 1.117, E2 = 1.312, E1 = 1.662
"." = curve for q1 = 1.76 m²/s, ":" = curve for q2 = 2.011 m²/s
Point (1) is on the upper (subcritical) limb of the curve for m²/s; point (2) is on the upper limb of the curve for m²/s, shifted left by m.
Answer: depth over the hump m, water surface elevation there m (above the upstream bed); upstream elevation m (unchanged).
✓ Answer checked by Claude Opus 5.5 (high effort)
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