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Unit hydrograph and UH for multiple storms

Short answer

Unit hydrograph is the DRH from 1 cm effective rainfall uniformly over a basin in duration D. For multiple storms, deconvolute: solve Q_n = Σ P_m U_{n-m+1} successively, starting U1=Q1/P1, U2=(Q2−P2U1)/P1, etc., and check volume equals 1 cm over area.

What is unit hydrograph (UH)? How do you prepare UH for multiple storm?

Unit hydrograph

A unit hydrograph is the direct runoff hydrograph produced by 1 cm of effective rainfall, falling uniformly over the basin at a constant rate during a specified duration DD. It assumes linearity and time invariance.

Preparing a UH from a multiple (complex) storm

When a storm has several periods of effective rainfall, the observed direct runoff hydrograph (DRH) is the sum of the responses to each period. The UH is obtained by deconvolution.

Steps

  1. Separate the baseflow from the storm hydrograph to get the DRH ordinates QnQ_n.
  2. Compute the effective rainfall for each period of duration DD by deducting losses (ϕ\phi-index): P1,P2,…,PMP_1, P_2, \dots, P_M.
  3. The DRH ordinate at time nn is
Qn=∑m=1min⁡(n,M)Pm Un−m+1Q_n=\sum_{m=1}^{\min(n,M)} P_m\,U_{n-m+1}
  1. Solve for the UH ordinates UnU_n successively:
U1=Q1P1,U2=Q2−P2U1P1,U3=Q3−P2U2−P3U1P1, …U_1=\frac{Q_1}{P_1},\quad U_2=\frac{Q_2-P_2U_1}{P_1},\quad U_3=\frac{Q_3-P_2U_2-P_3U_1}{P_1},\ \dots
  1. Check that the area under the UH equals 1 cm over the basin: ∑U Δt=1 cm×A\sum U\,\Delta t = 1\ \text{cm}\times A.
  2. For more accuracy, use many storms and the least-squares method, and average the UH ordinates.

Example

Two periods of 1 h with effective rainfall P1=2P_1=2 cm and P2=3P_2=3 cm. Observed DRH: Q1=20Q_1=20, Q2=90Q_2=90, Q3=130Q_3=130, Q4=80Q_4=80, Q5=30Q_5=30 m3^3/s.

nWorkingUnU_n (m3^3/s)
120/210
2(90 - 3x10)/230
3(130 - 3x30)/220
4(80 - 3x20)/210
5(30 - 3x10)/20

The 1-h UH ordinates are 10, 30, 20, 10 m3^3/s at 1, 2, 3, 4 h.

✓ Answer checked by Claude Sonnet 5.5

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