- 2080 Bhadra · 1+4 marks
How transformation reduces design steps; band stop design
Short answer
Frequency transformation eliminates separate approximation for each filter type; band-stop specs map to a low-pass equivalent, then standard tables give elements, which are transformed by fixed formulas. For ω₀=2000 rad/s, B=400 rad/s, prototype L1=1 H, C2=2 F, L3=1 H becomes series arms 0.1 mH∥2.5 mF, shunt 1.25 mH in series with 0.2 mF.
How frequency transformation reduces the design steps required to design a filter? Design a band stop filter having center frequency 2000 rad/s and bandwidth 400 rad/s from a 3rd order Butterworth low pass filter. (Refer Table)
How frequency transformation reduces design steps
Without frequency transformation, a band-stop filter would need its own approximation (finding a suitable with the required notch band) and its own synthesis, which is long and error-prone. With frequency transformation:
- The band-stop specification is converted to an equivalent normalized low-pass specification.
- The order and the ladder element values are read directly from the standard low-pass table (no new approximation).
- Each element of the low-pass ladder is replaced by a simple LC pair using fixed formulas (no new synthesis).
So one set of low-pass tables, plus a few substitution rules, covers HP, BP and BS designs.
Design of the band-stop filter
The LP → BS transformation is . Element rules:
- series → parallel tank in the series arm: , ;
- shunt → series LC in the shunt arm: , .
Prototype from the table (, ): series H, shunt F, series H.
Rs=1 [ Z1 ] [ Z3 ]
o-/\/\--[ ]---+------[ ]---+-----o
| | | +
Vs [ Y2 ] RL=1 Vo
| | | -
o----------------+---------------+-----o
| Arm | Prototype | Band-stop element |
|---|---|---|
| Z1 (series) | H | 0.1 mH ∥ 2.5 mF (tank) |
| Y2 (shunt) | F | 1.25 mH in series with 0.2 mF |
| Z3 (series) | H | 0.1 mH ∥ 2.5 mF (tank) |
Check: rad/s. Band edges: and rad/s (3 dB points).
These values are for terminations. For practical values, magnitude-scale by (e.g. for 1 kΩ terminations): multiply every L by and divide every C by .
✓ Answer checked by Claude Sonnet 5.5
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